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Date: Sun, 14 Mar 2021 14:51:30 -0700 (PDT)
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Subject: Re: Master Mind from Journeyman project
From: leflynn <leflynn@hotmail.com>
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On Friday, March 12, 2021 at 6:01:00 AM UTC-5, Anton Shepelev wrote:
> leflynn:=20
>=20
> > Let=D0=A2s start with five colors represented by a, b, c, d and
> > e. There are 10 possible choices for the three colors not=20
> > counting positioning. I would list the ten cases and then=20
> > cross them off when they are eliminated.
> Yes, finding a combination instead of a permutation is much=20
> easier. I still, however, am at a loss about solving the=20
> original problem as fast as the game requires.=20
>=20
> --=20
> () ascii ribbon campaign - against html e-mail=20
> /\ http://preview.tinyurl.com/qcy6mjc [archived]

I see finding a combination as part of the problem fortunately, you can do =
both at once.

Here is a decision table. You'll need to view it with a fixed width font.
 G1   G2   G3   G4   G5
(ABC)=20
 3p0 (BCA)(CAB)
 3p1 (ACB)(BAC)(CBA)=20
 2p0 (BAD)=20
      3p1 (BDA)(DAB)
      2p0 (CDA)
           3p0 (DCA)
           2p0 (DCB)
           2p2 (CDB)=20
      2p1 (BEA) (EAB)
      2p2 (BAE)(BCD)(CAD)
      1p0 (CEA)=20
           3p1 (ECA)
           2p0 (ECB)=20
           2p2 (CEB)
      1p1 (CAE)(BCE)
 2p1 (ADB)
      3p0 (DBA)
      2p0 (CBD)
           3p0 (BDC)
           1p0 (DAC)
           1p1 (EBA)=20
      2p1 (ACD)
      2p2 (AEB)
      1p0 (BEC)
           3p0 (CBE)
           2p1 (EAC)=20
      1p1 (ACE)
 2p2 (ABD)
      2p2 (ABE)
      2p1 (ADC)(DBC)
      1p1 (AEC)(EBC)
 1p0 (DAE)
      3p0 (EDA)
      3p1 (DEA)(EAD)
      2p0 (BED)
           3p0 (EDB)
           3p1 (DEB)=20
           2p0 (ECD)=20
           2p2 (CED)
      2p1 (BDE)(CDE)
      2p2 (DCE)
 1p1 (ADE)=20
      3p1 (AED)
      2p0 (DEC)(EBD)
      2p1 (DBE)(EDC)

Is (DCE) in the correct place?
  Guess1(ABC) 1p0; Guess2(DAE) 2p2; Guess3 (DCE)
Is (CAD) in the correct place?
  Guess1(ABC) 2p0; Guess2(BAD) 2p2; Guess3(BAE) 1P; Guess4(BCD) 2p1; Guess5=
(CAD)