X-Received: by 2002:ae9:c00e:: with SMTP id u14mr4518102qkk.293.1642864665734; Sat, 22 Jan 2022 07:17:45 -0800 (PST) X-Received: by 2002:a25:a101:: with SMTP id z1mr13143782ybh.310.1642864665468; Sat, 22 Jan 2022 07:17:45 -0800 (PST) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.rec.philatelie Date: Sat, 22 Jan 2022 07:17:45 -0800 (PST) In-Reply-To: Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e34:ec79:2580:112a:f6ec:1739:6030; posting-account=s6JuvQoAAACDhXvSUSV0MgTIKro9bciz NNTP-Posting-Host: 2a01:e34:ec79:2580:112a:f6ec:1739:6030 References: User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <1f3e67a9-a3a1-4f6d-b3fd-13d26821779fn@googlegroups.com> Subject: Re: Bayern 12 kreuzen lilas armoirie From: antoin Injection-Date: Sat, 22 Jan 2022 15:17:45 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 1806 Lines: 13 Bonjour Finalement j'ai pu faire une photo du filigrane et je me suis aper=C3=A7u q= ue je l'avais mal m=C3=A9moris=C3=A9 en faisant mon sch=C3=A9ma. La grande diagonale du losange fait beaucoup moins; je trouve en mesurant 15,6 mm mais les contours du losange ne sont pas =C3= =A9vidents. faut-il prendre l'int=C3=A9rieur ou l'ext=C3=A9rieur du losange? Il faut trouver soit 14 mm soit 17 mm car il y a 2 types de filigrane tr=C3= =A8s semblables =C3=A0 la dimension pr=C3=A8s. https://www.cjoint.com/c/LAwpfNb43Cx Amiti=C3=A9s et bon week-end