X-Received: by 2002:a05:620a:4556:: with SMTP id u22mr18910862qkp.631.1643215043686; Wed, 26 Jan 2022 08:37:23 -0800 (PST) X-Received: by 2002:ad4:5bc1:: with SMTP id t1mr25186288qvt.72.1643215043478; Wed, 26 Jan 2022 08:37:23 -0800 (PST) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.chimie Date: Wed, 26 Jan 2022 08:37:23 -0800 (PST) Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:4285:f740:a1cb:f334:790f:a6aa; posting-account=zQoBXgoAAACxMaoYUtQrWLHuLDvFRjsK NNTP-Posting-Host: 2001:861:4285:f740:a1cb:f334:790f:a6aa User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <8f57222d-a63c-44b1-8d28-77af5cb068ecn@googlegroups.com> Subject: acide-base From: Dutrieux Maud Injection-Date: Wed, 26 Jan 2022 16:37:23 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 1415 Lines: 9 bonjours je dois r=C3=A9aliser une =C3=A9quation =C3=A0 trou et elle me blo= que=20 L'=C3=A9quation de dosage de la soude par l'acide oxalique (symbolis=C3=A9 = AH2) est la suivante : 2... + 1... ---->1... + 2.....=20 ma r=C3=A9ponse qui est donc fausse est=20 2AH2 + 1 H2O ----->1A2- + 2H3O+ sachant que la soude est compos=C3=A9e de HO- et NA+=20 je suis perdu pouvez vous m'aider?