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Failed to connect to MySQL: (1203) User howardkn already has more than 'max_user_connections' active connectionsX-Received: by 2002:a05:620a:c53:b0:748:59c2:c071 with SMTP id u19-20020a05620a0c5300b0074859c2c071mr364137qki.4.1683304418171; Fri, 05 May 2023 09:33:38 -0700 (PDT) X-Received: by 2002:a5b:60a:0:b0:b9d:d623:1960 with SMTP id d10-20020a5b060a000000b00b9dd6231960mr939546ybq.0.1683304417890; Fri, 05 May 2023 09:33:37 -0700 (PDT) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Fri, 5 May 2023 09:33:37 -0700 (PDT) In-Reply-To: Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:f18b:694a:1f3d:88f; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:f18b:694a:1f3d:88f References: <392fbb1b-e0ce-472e-8238-9b64d144f409n@googlegroups.com> <36518896-aa01-45ff-a4e0-1bffca0e21dan@googlegroups.com> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: Subject: =?UTF-8?Q?Re=3A_Le_probl=C3=A8me_de_bite_chez_Hachel?= From: Richard Verret Injection-Date: Fri, 05 May 2023 16:33:38 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2887 Lines: 16 Le vendredi 5 mai 2023 =C3=A0 18:12:11 UTC+2, Python a =C3=A9crit=C2=A0: > Un peu quand m=C3=AAme, vu que vous r=C3=A9p=C3=A9tez les m=C3=AAme sotti= ses=20 > m=C3=AAme on on vous explique pourquoi ce sont des sottises. Le probl=C3=A8me est que nous pensons chacun avoir raison. Voil=C3=A0 mon approche. Nous avons deux espaces E et E=E2=80=99 distincts, c=E2=80=99est =C3=A0 dir= e en mouvement l=E2=80=99un par rapport =C3=A0 l=E2=80=99autre. Au temps t = =3D 0 de E un point M=E2=80=99 de E=E2=80=99 co=C3=AFncide avec un point M = de E.=20 Le point M=E2=80=99 a pour coordonn=C3=A9es (x=E2=80=99, y=E2=80=99, z=E2= =80=99) dans E=E2=80=99. On peut garder ces coordonn=C3=A9es pour le situer= dans E. Les coordonn=C3=A9es du vecteur OM=E2=80=99 seront alors (x=E2=80= =99, y=E2=80=99, z=E2=80=99), les m=C3=AAmes que celles du vecteurs O=E2=80= =99M=E2=80=99 (x=E2=80=99, y=E2=80=99, z=E2=80=99). Reconnaissez qu=E2=80=99il y a risque de confusion. La question est donc de= quelles coordonn=C3=A9es parle-t-on ?