Path: ...!2.eu.feeder.erje.net!feeder.erje.net!feeder1.feed.usenet.farm!feed.usenet.farm!peer03.ams4!peer.am4.highwinds-media.com!news.highwinds-media.com!feed.abavia.com!abe004.abavia.com!abe002.abavia.com!proxad.net!feeder1-1.proxad.net!cleanfeed3-b.proxad.net!nnrp1-2.free.fr!not-for-mail Subject: Re: Factorisation x^4 + 4 Newsgroups: fr.sci.maths References: <6462222f$0$3096$426a74cc@news.free.fr> <6462226e$0$3096$426a74cc@news.free.fr> From: kurtz le pirate Organization: Compagnie de la Banquise Date: Fri, 19 May 2023 11:05:02 +0200 User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:78.0) Gecko/20100101 Thunderbird/78.14.0 MIME-Version: 1.0 In-Reply-To: Content-Type: text/plain; charset=utf-8 Content-Language: fr Content-Transfer-Encoding: 8bit Lines: 25 Message-ID: <64673bbf$0$2979$426a74cc@news.free.fr> NNTP-Posting-Date: 19 May 2023 11:05:03 CEST NNTP-Posting-Host: 90.107.43.253 X-Trace: 1684487103 news-2.free.fr 2979 90.107.43.253:52844 X-Complaints-To: abuse@proxad.net X-Received-Bytes: 1443 Bytes: 1656 On 15/05/2023 15:07, Olivier Miakinen wrote: > Bonjour, > > Le 15/05/2023 14:15, ast a écrit : >>> >>> On a: x^4 + 1 =  ((x+1)²+1)).((x-1)²-1) >> >> erreur >> >> x^4 + 1 = ((x+1)²+1)).((x-1)²+1) > > Corrigeons tout de suite la deuxième erreur, avec un 4 au lieu d'un 1 : > > x⁴ + 4 = ((x+1)²+1)).((x-1)²+1) mais si c'est x^4 + 4 ça donne : (x^2 - 2 x + 2) (x^2 + 2 x + 2) -- kurtz le pirate compagnie de la banquise