X-Received: by 2002:a05:620a:4482:b0:77f:1789:61da with SMTP id x2-20020a05620a448200b0077f178961damr9365qkp.0.1702058494621; Fri, 08 Dec 2023 10:01:34 -0800 (PST) X-Received: by 2002:a05:6808:1924:b0:3b9:e8d0:6de9 with SMTP id bf36-20020a056808192400b003b9e8d06de9mr425830oib.4.1702058494389; Fri, 08 Dec 2023 10:01:34 -0800 (PST) Path: ...!news.nobody.at!newsreader4.netcologne.de!news.netcologne.de!peer02.ams1!peer.ams1.xlned.com!news.xlned.com!peer02.iad!feed-me.highwinds-media.com!news.highwinds-media.com!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Fri, 8 Dec 2023 10:01:33 -0800 (PST) In-Reply-To: <5GV5w2DSL7R2h5H21SJKuervTQw@jntp> Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e0a:170:e3f0:99a3:d595:2cf2:9b61; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2a01:e0a:170:e3f0:99a3:d595:2cf2:9b61 References: <26433c92-7d7d-499d-bf35-0967a2e37b99n@googlegroups.com> <6618f818-ecae-4ce3-8f8d-6265268f0eccn@googlegroups.com> <5GV5w2DSL7R2h5H21SJKuervTQw@jntp> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <131630da-ff4e-4175-9fac-02d590fc19adn@googlegroups.com> Subject: =?UTF-8?B?UmU6IFBlbnPDqWUgcmVsYXRpdmlzdGUgKDIp?= From: Richard Verret Injection-Date: Fri, 08 Dec 2023 18:01:34 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Received-Bytes: 2016 Bytes: 2167 Lines: 7 Le 08/12/2023 =C3=A0 18:45, Yanick Toutain a =C3=A9crit : > Expliquez nous alors comment l'observateur conna=C3=AEt l'angle mu.=20 > Pour l'instant Richard Hachel refuse de l'expliquer.=20 > Il semble n'avoir AUCUNE ID=C3=89E de COMMENT FAIRE. De m=C3=AAme que l=E2=80=99observateur ne conna=C3=AEt pas les caract=C3=A9= ristiques de l=E2=80=99onde =C3=A9mise, il ne peut pas conna=C3=AEtre cet a= ngle. Je pense que seul un observateur qui observe l=E2=80=99observateur qu= i observe le corps en mouvement pourra d=C3=A9terminer cet angle.=20