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Failed to connect to MySQL: (1203) User howardkn already has more than 'max_user_connections' active connectionsPath: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: HenHanna Newsgroups: comp.lang.lisp Subject: Given string 'a.bc.' -- replace each dot(.) with 0 or 1 Date: Sat, 18 May 2024 01:31:32 -0700 Organization: A noiseless patient Spider Lines: 13 Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Sat, 18 May 2024 10:31:33 +0200 (CEST) Injection-Info: dont-email.me; posting-host="7c7ccf8d8ecc9b5171c5fa73857bd316"; logging-data="2845877"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+78RDE4Z5X7K1RhbvBfWwFsSoXlYT1IBo=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:xlJ7WU6mg0s1nIK2ZmI1l4mK7E0= Content-Language: en-US Bytes: 1426 How can i write this function simply? (in Common Lisp) -- Given a string 'a.bc.' -- replace each dot(.) with 0 or 1. -- So the value is a list of 4 strings: ('a0bc0' 'a0bc1' 'a1bc0' 'a1bc1') -- The order is not important. If the string has 3 dots, the value is a list of length 8. If the program is going to be simpler, pls use, e.g. (a $ b c $) rather than 'a.bc.'