Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: Richard Damon Newsgroups: sci.math Subject: Re: how Date: Fri, 26 Apr 2024 10:49:47 -0400 Organization: i2pn2 (i2pn.org) Message-ID: References: <0fb574df-6dab-465b-9de7-97f0826d7f9e@att.net> <5CEq-_0rkY18kpL2FG3KH65W0Lg@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Fri, 26 Apr 2024 14:49:47 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="2426171"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird In-Reply-To: Content-Language: en-US X-Spam-Checker-Version: SpamAssassin 4.0.0 Bytes: 2034 Lines: 41 On 4/26/24 10:41 AM, WM wrote: > Le 26/04/2024 à 04:03, Richard Damon a écrit : > >>> If ω is existing, then something is next. >> >> next above, yes, ω+1 >> >> next below, no, > > I disagree. Which makes you wrong. > >> the problem is the set below it is unbounded, > > The set is bounded by ω. But ω isn't in the set, so it can't be the upper bound of the set that is below ω Your logic just said that ω is the number before ω, so got stuck in a infinite loop. After all, if the number below ω is the upper bound of the set of Natural Numbers, and that is itself ω, then the number below ω must be ω by your logic. BOOM. > >> and thus doesn't have a "highest" value in it. > > The value is there but invisible. > Nope. No such thing. > Regards, WM > >