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Subject: Exercice pour les jeunes
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Date: Sat, 01 Jun 24 12:22:47 +0000
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From: Richard Hachel <richard.hachel@invalid.fr>
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On pose :
3x+y=13
x+3y=15

Baccalauréat S : Toulon, cession de septembre 2023.

J'ai essayé comme ceci:
3x+y=13
z=13 
Z=3x-2y+2y+3y

Z=9x+4-2y+(-6x+6x)

Z=8+a²-2ab+b²
 d'où x=2 et y=1.

Que pensez-vous de cette nouvelle méthode? 

R.H.