Path: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: Cursitor Doom Newsgroups: sci.electronics.design Subject: Re: A Complex Metaphysical Conundrum Date: Thu, 11 Apr 2024 13:59:24 +0100 Organization: A noiseless patient Spider Lines: 22 Message-ID: References: MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Injection-Date: Thu, 11 Apr 2024 14:59:25 +0200 (CEST) Injection-Info: dont-email.me; posting-host="3ee569d00c4084ce2e4c35b0d486ea2c"; logging-data="1793895"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+imYgdGluj8YPqibcp/8mfbo217vr5aFI=" User-Agent: ForteAgent/8.00.32.1272 Cancel-Lock: sha1:4PuMF0+IC4d3aBds/bVSEVDUf+g= Bytes: 1737 On Thu, 11 Apr 2024 06:38:30 -0000 (UTC), Jasen Betts wrote: >On 2024-04-10, Cursitor Doom wrote: >> Gentlemen, >> >> This is an exam question that trips up even some of the best students. >> See what you make of it! >> >> Q: Is this statement correct: 'The signal level at the modem input >> increased by 2dBmV going from +3dBmV to +5dBmV.' >> >> Your pal, CD. > >db is a logarythmic ratio. an increase from +3dBmV to +5dBmV is an increase by 2dB >(not 2dBmV) > >Adding 2dBmV to +3dBmV will not get you +5dBmV because it's a >logarythmic scale. The question does require a "correct/incorrect" answer. It's a binary choice. Your answer is....?