Path: ...!fu-berlin.de!uni-berlin.de!news.dfncis.de!not-for-mail From: Luigi Fortunati Newsgroups: sci.physics.research Subject: Equivalence principle Date: Sat, 8 Jun 2024 19:40:15 +0200 Organization: A noiseless patient Spider Lines: 31 Approved: hees@itp.uni-frankfurt.de (sci.physics.research) Message-ID: X-Trace: news.dfncis.de SQkgMbCOXPjQ2bcH/+OKrQr3pKX+8H6y3e0b2PAuWXfheywtJUwWPsDZEtVIDatJY+ Cancel-Lock: sha1:e6JVd1BJ7NtRlM+pE+5+gNw12U8= sha256:5lHSLKRwpGmgIAJ/PtaAKkui/AgqWyvNLCoMAH9c+wM= Bytes: 2049 [Moderator's note: In the moderation process for this posting, I've cut by accident the first lines of the message; so here's there complete posting again. HvH] In the video https://www.youtube.com/watch?v=R3LjJeeae68 at minute 6:56 it states that there is no measurement that can be made to distinguish whether you’re being accelerated or whether you are sitting still on the surface of a planet. So, I ask: what stops us from measuring the presence (or absence) of tidal forces? If tidal forces are there, then we are stationary on the surface of a planet, if they are not there, we are experiencing a non-gravitational acceleration. Luigi Fortunati [Moderator's remark: One has to keep in mind that the equivalence principle is a local concept, i.e., the equivalence between the observations in a gravitational field and in an accelerated frame of reference in free space refers only to very small space-time regions. A "true gravitational field" is of course never entirely equivalent to an accelerated frame in flat Minkowski space, because according to GR the gravitational field leads to space-time curvature, i.e., a non-vanishing Riemann tensor, while Minkowski space is flat, which are coordinate-independent notions, and only such notions are physically interpretable. Of course tidal forces are well observable, cf. the tides on Earth, where the name "tidal force" refers to. HvH.]