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On 16/08/2024 18:56, Keith Thompson wrote:
> David Brown <david.brown@hesbynett.no> writes:
> [...]
>> In C++, you can't pass arrays as parameters at all - the language
>> inherited C's handling of arrays.  You can, of course, pass objects of
>> std::array<> type by value or by reference, just like any other class
>> types.
> 
> #include <cassert>
> 
> typedef int array42[42];
> 
> void func(array42& param) {
>      assert(sizeof param == 42 * sizeof(int));
> }
> 
> int main() {
>      array42 arg = { };
>      func(arg);
> }

This works in C too. You don't need by-reference parameters, but you do 
need to switch sizeof to work directly on the type:


  #include <assert.h>

  typedef int array42[42];

  void func(array42 param) {
      assert(sizeof(array42) == 42 * sizeof(int));
  }

  int main() {
      array42 arg = {0};
      func(arg);
  }