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From: "Steven G. Kargl" <sgk@REMOVEtroutmask.apl.washington.edu>
Newsgroups: comp.lang.fortran
Subject: Re: Is there a way in Fortran to designate an integer value as
 integer*8 ?
Date: Thu, 3 Oct 2024 22:40:07 -0000 (UTC)
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On Thu, 03 Oct 2024 22:28:31 +0100, Clive Page wrote:

> On 03/10/2024 20:59, Steven G. Kargl wrote:
>> My personal recommendation would be to do a proper porting from
>> integer (aka integer*4) to integer(kind=8).  And, yes, 8 in the
>> 'kind=8' is not portable.
>> 
> 
> Yes because different compilers use different integer kind numbers for 
different purposes: at least one uses kinds 1, 2, 3, 4 for the four most 
common numbers of bytes where other compilers use 1, 2, 4, 8.   But if you 
use integer(kind=int64) this is portable.

(Although unlikely) what happens when int64 = -1?
I suppose 'integer(-1)' is portable to the extent
that a compiler will error out.

-- 
steve