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Path: ...!3.eu.feeder.erje.net!feeder.erje.net!proxad.net!feeder1-2.proxad.net!usenet-fr.net!pasdenom.info!from-devjntp Message-ID: <-RLU4Hb-vC0H6CrJfdC09_wtGwc@jntp> JNTP-Route: news2.nemoweb.net JNTP-DataType: Article Subject: Re: Sync two clocks References: <u18wy1Hl3tOo1DpOF6WVSF0s-08@jntp> <v9nant$1d2us$1@dont-email.me> <vPP1Z1BJfE1Dt7SYhCzEo7ZQWFI@jntp> <va0a4f$30p95$1@dont-email.me> <Zwwc8OsxqpAwTzvPkie6NmgxmY8@jntp> <va1tp9$3c0qh$1@dont-email.me> <lvwOM_tj8NJtPtaduqcmSRprOtk@jntp> <va2b62$3c12c$15@dont-email.me> <gQSP7T04xKx9wgapoySeijcbJi4@jntp> <va2cu7$3c12c$17@dont-email.me> Newsgroups: sci.physics.relativity JNTP-HashClient: aVSJ7JCWYe8mJ9L_3ILo5-uO6SI JNTP-ThreadID: KqCy9G15x7A9xZN_JLsoNRe49xU JNTP-Uri: http://news2.nemoweb.net/?DataID=-RLU4Hb-vC0H6CrJfdC09_wtGwc@jntp User-Agent: Nemo/0.999a JNTP-OriginServer: news2.nemoweb.net Date: Tue, 20 Aug 24 16:18:52 +0000 Organization: Nemoweb JNTP-Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/127.0.0.0 Safari/537.36 Injection-Info: news2.nemoweb.net; posting-host="e8cbf2474b472b9bb79db3dccb6a856bc1d05409"; logging-data="2024-08-20T16:18:52Z/8994006"; posting-account="4@news2.nemoweb.net"; mail-complaints-to="julien.arlandis@gmail.com" JNTP-ProtocolVersion: 0.21.1 JNTP-Server: PhpNemoServer/0.94.5 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-JNTP-JsonNewsGateway: 0.96 From: Richard Hachel <r.hachel@jesauspu.fr> Bytes: 2438 Lines: 32 Le 20/08/2024 à 17:32, Python a écrit : >> In short, for A, tB and tA' are simultaneous. >> I repeat, for A, tB and tA' are simultaneous. > > Numbers like t_B or t'_A cannot be "simultaneous". Events > like e1 = "B sends back a light signal to A" or e2 = "A receives > this signal" can be. > > If this is what you meant, which is likely, then, according > to Einstein-Poincaré *definition* of simultaneity: > > e1 and e2 are NOT simultaneous for A (nor for B) No. YOU, you say that e1 and e2 are not simultaneus for A. That's not what I said. For B, the time e2-time e1 = 2AB/c C'est bon, tu comprends? Je suis sûr que tu planes, et que ça va encore être de ma très grande faute. Jean-Pierre, au moins une fois dans ta vie, je te supplie d'être sérieux. Fais un petit effort, bon sang!!! R.H.