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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: Sufficient knowledge of C proves that DD specifies
 non-terminating behavior to HHH
Date: Sat, 8 Feb 2025 17:28:53 -0500
Organization: i2pn2 (i2pn.org)
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 <228a9804d6919149bac728ccf08134ed90db121e@i2pn2.org>
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On 2/8/25 10:01 AM, olcott wrote:
> On 2/8/2025 5:50 AM, Richard Damon wrote:
>> On 2/8/25 12:53 AM, olcott wrote:
>>> On 2/7/2025 7:27 PM, Richard Damon wrote:
>>>> On 2/7/25 8:12 PM, olcott wrote:
>>>>> On 2/7/2025 5:56 PM, Richard Damon wrote:
>>>>>> On 2/7/25 11:26 AM, olcott wrote:
>>>>>>> On 2/7/2025 6:20 AM, Richard Damon wrote:
>>>>>>>> On 2/6/25 10:02 PM, olcott wrote:
>>>>>>>>> On 2/6/2025 8:21 PM, Richard Damon wrote:
>>>>>>>>>> On 2/6/25 5:18 PM, olcott wrote:
>>>>>>>>>>> On 2/6/2025 1:51 PM, Richard Damon wrote:
>>>>>>>>>>>> On 2/6/25 1:26 PM, olcott wrote:
>>>>>>>>>>>>> On 2/6/2025 10:52 AM, Bonita Montero wrote:
>>>>>>>>>>>>>> Am 05.02.2025 um 16:11 schrieb olcott:
>>>>>>>>>>>>>>> On 2/5/2025 1:44 AM, Bonita Montero wrote:
>>>>>>>>>>>>>>>> Am 05.02.2025 um 04:38 schrieb olcott:
>>>>>>>>>>>>>>>>> This treatment does not typically last very long and
>>>>>>>>>>>>>>>>> will be immediately followed by a riskier fourth line
>>>>>>>>>>>>>>>>> of treatment that has an initial success rate much higher
>>>>>>>>>>>>>>>>> than its non progression mortality rate.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Halting problem solved !
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> The halting problem proof input does specify non-halting
>>>>>>>>>>>>>>> behavior to its decider.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> https://www.researchgate.net/ 
>>>>>>>>>>>>>>> publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> LOOOOOOOOL
>>>>>>>>>>>>>
>>>>>>>>>>>>> Anyone that understands the C programming language
>>>>>>>>>>>>> sufficiently well (thus not confused by the unreachable
>>>>>>>>>>>>> "if" statement) correctly understands that DD simulated
>>>>>>>>>>>>> by HHH cannot possibly reach its own return instruction.
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> And anyone that understand the halting problem knows that 
>>>>>>>>>>>> isn't the question being asked. The quesiton you NEED to ask 
>>>>>>>>>>>> is will the program described by the input halt when run?
>>>>>>>>>>>>
>>>>>>>>>>>> Since you start off with the wrong question, you logic is 
>>>>>>>>>>>> just faulty.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> Everyone that thinks my question is incorrect is wrong.
>>>>>>>>>>> It has always been a mathematical mapping from finite
>>>>>>>>>>> strings to behaviors. That people do not comprehend this
>>>>>>>>>>> shows the shallowness of the depth of the learned-by-rote
>>>>>>>>>>> (lack of) understanding.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> No, you are just incorreect as you don't know what you are 
>>>>>>>>>> talking about.
>>>>>>>>>>
>>>>>>>>>> Yes, it is a mapping of the string to the behavior, and that 
>>>>>>>>>> mapping is DEFINED to be the halting behavior of the program 
>>>>>>>>>> the string describes.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> No this is incorrect. The input finite string specifies
>>>>>>>>> (not merely describes) non halting behavior to its decider.
>>>>>>>>>
>>>>>>>>
>>>>>>>> No, since the definition of "Halting Behavior" is the behavior 
>>>>>>>> of the progran being run.
>>>>>>>>
>>>>>>>
>>>>>>> It may seem that way to people that have learned-by-rote
>>>>>>> as their only basis. It is actually nothing like that.
>>>>>>
>>>>>> No, that *IS* the definition.
>>>>>>
>>>>>
>>>>> A termination analyzer computes the mapping from finite
>>>>> strings to the actual behavior that these finite strings
>>>>> specify. That this is not dead obvious to everyone here
>>>>> merely proves that learned-by-rote does not involve any
>>>>> actual comprehension.
>>>>>
>>>>>
>>>>
>>>> And the behavior the finite string specifies is the behavior of 
>>>> running the program. 
>>>
>>> That is verifiably factually incorrect.
>>> The running program has a different execution trace
>>> than the behavior that DD specifies to HHH.
>>>
>>
>> And where is the difference?
>>
> 
> typedef void (*ptr)();
> int HHH(ptr P);
> 
> int DD()
> {
>    int Halt_Status = HHH(DD);
>    if (Halt_Status)
>      HERE: goto HERE;
>    return Halt_Status;
> }
> 
> int main()
> {
>    HHH(DD);
> }
> 
> If you cannot tell that DD correctly simulated by HHH
> cannot possibly terminate normally then this proves that
> you lack sufficient technical competence to evaluate my work.
> 

All you have shown is that HHH (the one in the program provided) doesn't 
"correctly simulate" its input, as it aborts a halting program and calls 
it non-halting,

That you keep repeating this LIE after it has been explained just shows 
you are nothing but an ignorant pathological lying idiot.