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From: tomyee3@gmail.com (ProkaryoticCaspaseHomolog)
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Subject: Re: Want to prove =?UTF-8?B?RT1tY8KyPyBVbml2ZXJzaXR5IGxhYnMgc2hvdWxkIHRy?=
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Date: Sat, 23 Nov 2024 07:12:26 +0000
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On Fri, 22 Nov 2024 21:03:18 +0000, rhertz wrote:

> On Fri, 22 Nov 2024 20:30:39 +0000, Paul B. Andersen wrote:
>
> <snip all the history of your life. You didn't read my disclaimer>
>
>
>> Bottom line:
>> It doesn't matter how you put energy into a closed cavity.
>> In the cavity there will be a black body radiation with
>> temperature equal to the temperature of the walls.
>>
>> The reflectivity, albedo or colour of the inner surface
>> of the cavity are irrelevant. The radiation in the cavity
>> will always be black body radiation.
>>
>> Make a hole in your cavity, and you have a perfect
>> black body radiation source.
>>
>> Its temperature will not be very high, though-
>>
>>>
>>> Now smile, asshole.
>>
>> :-D
>
> It is not a BB radiation source!
>
> You ignored the fact that the heat goes away from the cavity. It doesn't
> remain neither inside nor outside. It's eliminated by cooling
> mechanisms, as I wrote as an initial condition. Read all the posts.
>
> There is no light energy left within the cavity, nor heat energy outside
> it. You better think again about it.

I'm sure that you didn't mean what you wrote.
A closed cavity at equilibrium above absolute zero will contain black
body radiation, regardless of the composition of its walls.

I haven't read what you mean by "cooling mechanisms", and since I'm
full-time employed, I haven't the leisure time to read all the posts.
So maybe I'm misunderstanding something, but I don't see what that
could be.

> You also ignored my post apologizing to all people that participated in
> this thread. That makes you a bigger ASSHOLE than what I thought.

Note the length of Paul's post. In all probability, he started his
post before you wrote your apology/disclaimer, and posted it without
seeing it. It was a natural mistake, not a deliberate act of spite.

Wars start because of such misunderstandings.

> Now, start thinking in my NEXT IDEA:
>
> Willing to try to prove/disprove E=mc² at a macroscopic level, I'll
> think of an experiment that incorporates electromagnetic oscillations
> passing through the cavity, which will be converted in a CAPACITOR, by
> cutting it in halves and isolating them with a thin ring.
>
> What I propose to MEASURE is the changes in the frequency of the LC
> oscillator, within a time window of about 3 msec, which repeats
> permanently.
>
> I'll use a relationship between mass and capacitance for the cavity,
> with frequency around 1 Mhz or greater.
>
> It was a failed idea for an experiment, but there are OTHER WAYS to
> check E=mc² at a macroscopic level, without resorting to nuclear energy
> crap (Kg evaporated vs. energy provided), or else.

Just for fun, I calculated the mass difference between a new and a
discharged CR123 lithium battery. I got 1.8e-10 grams.

c² is a pretty darn big number, and because of that, I don't think
that your frequency measurement proposal would work, even with the
latest generation atomic clocks monitoring the frequency of your LC
oscillator, since _your LC oscillator itself_ will have too low a Q
and will exhibit too much variability.
======================================================================
Of all the schemes I could think of whereby a DIY amateur scientist
can verify E=mc², the only feasible one that I can think of is to
measure the energy of electron-positron annihilation. I checked on
eBay for used equipment whereby a DIY experimenter could put together
a home arrangement. I myself could afford the materials, but I'd need
the help of an expert former EE to put things together (hint, hint).

Sealed sodium-22 positron sources are readily available for sale
online.

Calibrating the gamma-ray detectors will be the hard part. Once
calibrated, I'd place two gamma-ray detectors 180 degrees apart
equidistant from an appropriate target. Connected to the detectors
will be a whole slew of equipment for coincidence counting, energy
measurement, etc. that the expert former EE will be responsible for.

With luck, the DIY experimenter will be able to confirm the
simultaneous emission of two 511 keV photons from each annililation.