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X-Received: by 2002:a05:622a:60e:b0:42c:2a20:908f with SMTP id z14-20020a05622a060e00b0042c2a20908fmr5433qta.7.1707157957028; Mon, 05 Feb 2024 10:32:37 -0800 (PST) X-Received: by 2002:a05:6902:2402:b0:dc6:d3c0:ebe0 with SMTP id dr2-20020a056902240200b00dc6d3c0ebe0mr65977ybb.0.1707157956710; Mon, 05 Feb 2024 10:32:36 -0800 (PST) Path: ...!feeds.phibee-telecom.net!3.eu.feeder.erje.net!feeder.erje.net!proxad.net!feeder1-2.proxad.net!209.85.160.216.MISMATCH!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Mon, 5 Feb 2024 10:32:36 -0800 (PST) In-Reply-To: <DW92nFHJWuLhj8tja7lpdnF-2Zc@jntp> Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e0a:170:e3f0:834:7eb3:460d:7012; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2a01:e0a:170:e3f0:834:7eb3:460d:7012 References: <DW92nFHJWuLhj8tja7lpdnF-2Zc@jntp> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <0c5dcdc8-c6a8-4b14-ac46-9a2b21239ff2n@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_Le_probl=C3=A8me_de_l=27anisochronie_relativiste=2E?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Mon, 05 Feb 2024 18:32:37 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2446 Lines: 15 Le 05/02/2024 =C3=A0 16:58, Julien Arlandis a =C3=A9crit : > C'est pour =C3=A7a que j'ai =C3=A9voqu=C3=A9 UN espace des phases. Merci de cette pr=C3=A9cision! Dans mes premi=C3=A8res tentatives de public= ation je m=E2=80=99=C3=A9tais adress=C3=A9 =C3=A0 l=E2=80=99Institut Lois d= e Broglie, j=E2=80=99avais =C3=A9voqu=C3=A9 l=E2=80=99espace des phases, ma= is =C3=A7a ne leur a pas plu. Mais mon espace g=C3=A9n=C3=A9ral est bien mi= eux que l=E2=80=99espace des phases. Comme je le disais, il repr=C3=A9sente= l=E2=80=99univers entier, "o=C3=B9 les corps viennent prendre place", il e= st homog=C3=A8ne, et on peut travailler dessus. On d=C3=A9finit la fonction f(z) =3D m z =3D mx + my et on pose que l=E2=80= =99impulsion p est =C3=A9gale =C3=A0 p=3D my. En d=C3=A9rivant f on obtient= : df/dt =3D mv + mu, avec v =3D dx/dt et u =3D dy/dt, mv est la quantit=C3= =A9 de mouvement q =3D mv. La somme des forces ext=C3=A9rieures F est =C3= =A9gale, par d=C3=A9finition, =C3=A0 F =3D dp/dt, on obtient donc F =3D mu,= et df/dt =3D q + i F. Et voili et voilou!