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Path: ...!feeds.phibee-telecom.net!weretis.net!feeder8.news.weretis.net!pasdenom.info!from-devjntp Message-ID: <0urLk9tzygU8hLyD_kwRho5GpbQ@jntp> JNTP-Route: news2.nemoweb.net JNTP-DataType: Article Subject: Re: There is a first/smallest integer (in =?UTF-8?Q?M=C3=BCckenland=29?= References: <v78aei$1qhrg$2@dont-email.me> <iez0JhnP5QUwPTJ47oubeE1Aq5M@jntp> <v78m28$1sk3g$1@dont-email.me> <7mXj2D8kEhAscu3HLTqTUKsaj18@jntp> <d9b0dacd61b979099d931df69cf76c214d690d39@i2pn2.org> <Eb-CQaKSaHkMpWykEcQGtifvbV0@jntp> <45c2168329b760983a8cbc9139b6decf1a1edf5b@i2pn2.org> <v79af9$20iae$1@dont-email.me> Newsgroups: sci.math JNTP-HashClient: 7hAOu1ZmRQ1wNF3Wo3KnLbqbUsI JNTP-ThreadID: v78aei$1qhrg$2@dont-email.me JNTP-Uri: http://news2.nemoweb.net/?DataID=0urLk9tzygU8hLyD_kwRho5GpbQ@jntp User-Agent: Nemo/0.999a JNTP-OriginServer: news2.nemoweb.net Date: Wed, 17 Jul 24 21:17:17 +0000 Organization: Nemoweb JNTP-Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 Safari/537.36 Injection-Info: news2.nemoweb.net; posting-host="82b75c1d0a83e677ff646b52485f72f8b23749df"; logging-data="2024-07-17T21:17:17Z/8953062"; posting-account="217@news2.nemoweb.net"; mail-complaints-to="julien.arlandis@gmail.com" JNTP-ProtocolVersion: 0.21.1 JNTP-Server: PhpNemoServer/0.94.5 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-JNTP-JsonNewsGateway: 0.96 From: WM <wolfgang.mueckenheim@tha.de> Bytes: 2248 Lines: 19 Le 17/07/2024 à 22:44, Moebius a écrit : > Am 17.07.2024 um 22:37 schrieb joes: >> Am Wed, 17 Jul 2024 17:17:54 +0000 schrieb WM: > >>> ℵo finite intervals do not fit between [0, 1] and (0, 1]. > >> Where do you get this requirement from? > > Please tell us what "requirement" you are talking about (using > mathematical terminology/language/symbols). ℵo unit fractions occupy at least ℵo points and ℵo finite intervals. Therefore NUF(x) cannot change from 0 to ℵo without passing an interval of 2^ℵo points. They must be subtracted from your claim ∀ x > 0: NUF(x) = ℵo. Corrected ∀ x > 2^ℵo positive points: NUF(x) = ℵo. Regards, WM