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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: How to write a self-referencial TM?
Date: Mon, 19 May 2025 13:44:21 +0300
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On 2025-05-18 20:57:03 +0000, olcott said:

> On 5/18/2025 3:35 PM, wij wrote:
>> On Sat, 2025-05-17 at 14:39 -0500, olcott wrote:
>>> On 5/17/2025 2:26 PM, wij wrote:
>>>> On Sat, 2025-05-17 at 15:45 +0100, Mike Terry wrote:
>>>>> On 17/05/2025 04:01, wij wrote:
>>>>>> On Fri, 2025-05-16 at 23:51 +0100, Mike Terry wrote:
>>>>>>> On 16/05/2025 20:35, wij wrote:
>>>>>>>> On Fri, 2025-05-16 at 16:33 +0100, Mike Terry wrote:
>>>>>>>>> On 16/05/2025 12:40, wij wrote:
>>>>>>>>>> On Fri, 2025-05-16 at 03:26 +0100, Mike Terry wrote:
>>>>>>>>>>> On 16/05/2025 02:47, wij wrote:
>>>>>>>>>>>> On Fri, 2025-05-16 at 01:40 +0100, Mike Terry wrote:
>>>>>>>>>>>>> On 15/05/2025 19:49, wij wrote:
>>>>>>>>>>>>>> On Thu, 2025-05-15 at 17:08 +0100, Mike Terry wrote:
>>>>>>>>>>>>>>> On 14/05/2025 18:53, wij wrote:
>>>>>>>>>>>>>>>> On Wed, 2025-05-14 at 12:24 -0500, olcott wrote:
>>>>>>>>>>>>>>>>> On 5/14/2025 11:43 AM, wij wrote:
>>>>>>>>>>>>>>>>>> On Wed, 2025-05-14 at 09:51 -0500, olcott wrote:
>>>>>>>>>>>>>>>>>>> On 5/14/2025 12:13 AM, wij wrote:
>>>>>>>>>>>>>>>>>>>> Q: Write a turing machine that performs D function (which calls
>>>>>>>>>>>>>>>>>>>> itself):
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>> void D() {
>>>>>>>>>>>>>>>>>>>>           D();
>>>>>>>>>>>>>>>>>>>> }
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>> Easy?
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> That is not a TM.
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>> It is a C program that exists. Therefore, there must be a equivalent
>>>>>>>>>>>>>>>>>> TM.
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> To make a TM that references itself the closest
>>>>>>>>>>>>>>>>>>> thing is a UTM that simulates its own TM source-code.
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>> How does a UTM simulate its own TM source-code?
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> You run a UTM that has its own source-code on its tape.
>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>> What is exactly the source-code on its tape?
>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> Every UTM has some scheme which can be applied to a (TM & input tape) that
>>>>>>>>>>>>>>> is to
>>>>>>>>>>>>>>> be
>>>>>>>>>>>>>>> simulated.
>>>>>>>>>>>>>>> The
>>>>>>>>>>>>>>> scheme says how to turn the (TM + input tape) into a string of symbols that
>>>>>>>>>>>>>>> represent
>>>>>>>>>>>>>>> that
>>>>>>>>>>>>>>> computation.
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> So to answer your question, the "source-code on its tape" is the result of
>>>>>>>>>>>>>>> applying
>>>>>>>>>>>>>>> the
>>>>>>>>>>>>>>> UTM's
>>>>>>>>>>>>>>> particular scheme to the combination (UTM, input tape) that is to be
>>>>>>>>>>>>>>> simulated.
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> If you're looking for the exact string symbols, obviously you would need to
>>>>>>>>>>>>>>> specify
>>>>>>>>>>>>>>> the
>>>>>>>>>>>>>>> exact
>>>>>>>>>>>>>>> UTM
>>>>>>>>>>>>>>> being used, because every UTM will have a different answer to your question.
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> Mike.
>>>>>>>>>>>>>> 
>>>>>>>>>>>>>> People used to say UTM can simulate all TM. I was questing such a UTM.
>>>>>>>>>>>>>> Because you said "Every UTM ...", so what is the source of such UTM?
>>>>>>>>>>>>> 
>>>>>>>>>>>>> Yes, a UTM can simulate any TM including itself.  (Nothing magical changes when
>>>>>>>>>>>>> a
>>>>>>>>>>>>> UTM
>>>>>>>>>>>>> simulates
>>>>>>>>>>>>> itself, as opposed to some other TM.)
>>>>>>>>>>>> 
>>>>>>>>>>>> Supposed UTM exists, and denoted as U(X), X denotes the tape contents of the
>>>>>>>>>>>> encoding of a TM. And, U(X) should function the same like X.
>>>>>>>>>>>> Given instance U(U(f)), it should function like f from the above definition.
>>>>>>>>>>>> But, U(U(f)) would fall into a 'self-reference' trap.
>>>>>>>>>>> 
>>>>>>>>>>> There is no self-reference trap.
>>>>>>>>>>> 
>>>>>>>>>>> In your notation:
>>>>>>>>>>> 
>>>>>>>>>>> -  f represents some computation.
>>>>>>>>>>> -  U(f) represents U being run with f on its tape.
>>>>>>>>>>>         Note this is itself a computation, distinct from f of course
>>>>>>>>>>>         but having the same behaviour.
>>>>>>>>>>> -  U(U(f)) represents U simulating the previous computation.
>>>>>>>>>>> 
>>>>>>>>>>> There is no reason U(f) cannot be simulated by U.  U will have no 
>>>>>>>>>>> knowledge that it
>>>>>>>>>>> is
>>>>>>>>>>> "simulating
>>>>>>>>>>> itself", and will just simulate what it is given.
>>>>>>>>>>> 
>>>>>>>>>>> 
>>>>>>>>>>> Mike.
>>>>>>>>>> 
>>>>>>>>>> Sorry for not being clear on the UTM issue (I wanted to mean several 
>>>>>>>>>> things in one
>>>>>>>>>> post).
>>>>>>>>>> You are right there is no self-reference.
>>>>>>>>>> I mean 'UTM' is not a complete, qualified TM because the contents of the tape
>>>>>>>>>> would not be defined. Saying "UTM can simulate any TM" is misleading because
>>>>>>>>>> no such TM (UTM as TM) exists.
>>>>>>>>> 
>>>>>>>>> What do you mean "the contents of the tape would not be defined"?  A TM 
>>>>>>>>> is /equipped/
>>>>>>>>> with
>>>>>>>>> an
>>>>>>>>> infinite tape, but the /contents/ of that tape are not a part of that 
>>>>>>>>> TM's definition.
>>>>>>>>> 
>>>>>>>>> For example we could build a TM P that decides whether a number is 
>>>>>>>>> prime.  Given a
>>>>>>>>> number n,
>>>>>>>>> we
>>>>>>>>> convert n into the input tape representation of n, and run P with that 
>>>>>>>>> tape as input.
>>>>>>>>> 
>>>>>>>>> It's essentially no different for UTMs.  Such a UTM certainly is a 
>>>>>>>>> "complete TM",
>>>>>>>>> equipped
>>>>>>>>> with
>>>>>>>>> its
>>>>>>>>> own input tape.  Of course we don't know what's on the input tape 
>>>>>>>>> because nobody has
>>>>>>>>> said
>>>>>>>>> yet
>>>>>>>>> what
>>>>>>>>> computation we are asking it to simulate!  [Similarly we don't know 
>>>>>>>>> what's on P's input
>>>>>>>>> tape,
>>>>>>>>> until
>>>>>>>>> we know what n we want it to test for primeness.]  Once you say what 
>>>>>>>>> computation you
>>>>>>>>> want
>>>>>>>>> the
>>>>>>>>> UTM to
>>>>>>>>> simulate we can build a tape string to perform that particular 
>>>>>>>>> simulation.  That is the
>>>>>>>>> case
>>>>>>>>> /whatever/ computation we come up with, so it is simply the case [not 
>>>>>>>>> misleading] that
>>>>>>>>> the
>>>>>>>>> UTM
>>>>>>>>> can
>>>>>>>>> simulate any computation.
>>>>>>>>> 
>>>>>>>>> 
>>>>>>>>> Mike.
>>>>>>>> 
>>>>>>>> TM has no I/O mechanism. 'Computation' always means the contents of the tape
>>>>>>>> is defined (fixed before run).
>>>>>>>> 
>>>>>>> 
>>>>>>> Correct, and correct.
>>>>>>> 
>>>>>>> So... What do you mean "the contents of the tape would not be defined"?
>>>>>>> 
>>>>>>> 
>>>>>>> Mike.
>>>>>> 
>>>>>> In "UTM simulates itself", denoted as U(U(f)), the f would not be defined.
>>>>> 
>>>>> Eh?  The f was something /you/ introduced!  You said it represents some 
>>>>> computation which UTM U
>>>>> simulates.  How can f suddenly become undefined after you defined it?
>>>>> 
>>>>> Do you mean that f would not be on the input tape for (outer)U?  That's 
>>>>> not the case at all.  In
>>>>> U(f), the input tape for U contains a representation of f.  When 
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