| Deutsch English Français Italiano |
|
<100lkdv$32ib3$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail
From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_Analysis_of_Flibble=E2=80=99s_Latest=3A_Detecting_v?=
=?UTF-8?Q?s=2E_Simulating_Infinite_Recursion_ZFC?=
Date: Wed, 21 May 2025 17:34:39 -0500
Organization: A noiseless patient Spider
Lines: 73
Message-ID: <100lkdv$32ib3$1@dont-email.me>
References: <Ms4XP.801347$BFJ.668081@fx13.ams4>
<95db078e80b2868ed15a9a9a2af0280d96234a3a@i2pn2.org>
<100jo18$2mhfd$1@dont-email.me> <100jpv9$2m0ln$4@dont-email.me>
<100kt0c$2tae8$3@dont-email.me> <100ktr7$2reaa$1@dont-email.me>
<100l09v$2tae8$5@dont-email.me> <100l1ov$2ul3j$1@dont-email.me>
<100l3jh$2v0e9$1@dont-email.me> <100l5c8$2ul3j$2@dont-email.me>
<100l75g$2vpq3$1@dont-email.me> <100l887$2ul3i$2@dont-email.me>
<100l9gh$30aak$1@dont-email.me> <100lc4o$30pgm$1@dont-email.me>
<100ld1u$312c9$1@dont-email.me> <100lg4g$31jt3$1@dont-email.me>
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8; format=flowed
Content-Transfer-Encoding: 8bit
Injection-Date: Thu, 22 May 2025 00:34:40 +0200 (CEST)
Injection-Info: dont-email.me; posting-host="1445173336acf9f867010d2c7ad38e9f";
logging-data="3230051"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+khVctGxhseWGmAmKON7VG"
User-Agent: Mozilla Thunderbird
Cancel-Lock: sha1:lHsKhtnrxnQj8gXyYkyHNMCIrB0=
In-Reply-To: <100lg4g$31jt3$1@dont-email.me>
X-Antivirus-Status: Clean
Content-Language: en-US
X-Antivirus: Norton (VPS 250521-10, 5/21/2025), Outbound message
On 5/21/2025 4:21 PM, Richard Heathfield wrote:
> On 21/05/2025 21:28, olcott wrote:
>> On 5/21/2025 3:13 PM, Richard Heathfield wrote:
>>> On 21/05/2025 20:28, olcott wrote:
>
> <snip>
>
>>>> I have only been talking about the ACTUAL
>>>> conventional proof of the halting problem.
>>>
>>> The ACTUAL conventional proof of the Halting Problem goes something
>>> like this:
>>>
>>> 1) assume that it is possible to devise an algorithm that can
>>> determine in finitely many steps ascertain whether an arbitrary
>>> program applied to arbitrary data does or does not stop.
>>>
>>> 2) given such an algorithm, imagine incorporating it into a program
>>> that ascertains whether a supplied program with supplied data halts,
>>> loops if it does, and halts if it doesn't.
>>>
>>
>> This step is impossible.
>
> Correct. We have derived an impossible consequence of our assumption,
> thus proving that the assumption is false.
>
>> It only seemed possible
>
> No. It never seemed possible. It always seemed like the impossible
> contradiction that it is.
>
>> because no one ever
>> tried to completely encode every detail.
>
> Why would they? One would have to be pretty stupid to try.
>
>> This screwy mistake came about
>
> It's not screwy, and it's not a mistake. It's a proof that there is at
> least one thing which we'd like a computer to be able to do but which it
> will never be able to do.
>
> Like you said, it's impossible. QED.
>
>
>> because fools thought
>> that a halt decider H is supposed to report on the behavior
>> of the program that itself is contained within rather
>> than the behavior that its actual input actually specifies.
>
> What your halt decider reports on is entirely up to you, but thanks to
> Turing we know that it will not be able to act as a /universal/
> termination analyser that always gets the answer right regardless of the
> input.
>
> Sometimes? Sure. bool decide(whatever){return true;} will get it right
> sometimes. But for some inputs your decider will get it wrong.
>
>> int main()
>> {
>> DDD(); // No HHH can report on the behavior of its caller.
>> }
>
Show an actual input to HHH that actually does
the opposite of whatever value that HHH returns.
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer