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Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail
From: Richard Heathfield <rjh@cpax.org.uk>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_Analysis_of_Flibble=E2=80=99s_Latest=3A_Detecting_v?=
 =?UTF-8?Q?s=2E_Simulating_Infinite_Recursion_ZFC?=
Date: Mon, 26 May 2025 18:25:18 +0100
Organization: Fix this later
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On 26/05/2025 17:24, olcott wrote:
> On 5/26/2025 11:10 AM, Richard Heathfield wrote:
>> On 26/05/2025 16:42, olcott wrote:
>>> no
>>> C function can see its own caller.
>>
>> So because DDD calls HHH, HHH can't analyse the halting 
>> behaviour of DDD.
>>
>> Got it.
>>
> 
> I didn't say that.

Yes, you did.

On 24/5/2025 in Message-ID <100sr6o$ppn2$3@dont-email.me> you said:

> You are a damned liar when you say that I said
> that HHH must report on the behavior of its caller.
> 
> No HHH can report on the behavior of its caller
> for the same reason that no function can report
> on the value of the square-root of a dead cat.

Your words.

Since DDD is HHH's caller, according to you HHH can't report on 
DDD's behaviour.

> Functions computed by models of computation are only
> allowed to compute the mapping FROM THEIR INPUTS.

So you're arguing both that HHH is only allowed to compute a 
mapping from DDD *and* that it can't report on DDD.

Got it. Yes, that's very clear.

-- 
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
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