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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_Analysis_of_Flibble=E2=80=99s_Latest=3A_Detecting_v?=
 =?UTF-8?Q?s=2E_Simulating_Infinite_Recursion_ZFC?=
Date: Mon, 26 May 2025 14:18:02 -0500
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On 5/26/2025 2:14 PM, Richard Heathfield wrote:
> On 26/05/2025 18:29, olcott wrote:
>> On 5/26/2025 12:25 PM, Richard Heathfield wrote:
>>> On 26/05/2025 17:24, olcott wrote:
>>>> On 5/26/2025 11:10 AM, Richard Heathfield wrote:
>>>>> On 26/05/2025 16:42, olcott wrote:
>>>>>> no
>>>>>> C function can see its own caller.
>>>>>
>>>>> So because DDD calls HHH, HHH can't analyse the halting behaviour 
>>>>> of DDD.
>>>>>
>>>>> Got it.
>>>>>
>>>>
>>>> I didn't say that.
>>>
>>> Yes, you did.
>>>
>>> On 24/5/2025 in Message-ID <100sr6o$ppn2$3@dont-email.me> you said:
>>>
>>>> You are a damned liar when you say that I said
>>>> that HHH must report on the behavior of its caller.
>>>>
>>>> No HHH can report on the behavior of its caller
>>>> for the same reason that no function can report
>>>> on the value of the square-root of a dead cat.
>>>
>>> Your words.
>>>
>>> Since DDD is HHH's caller, according to you HHH can't report on DDD's 
>>> behaviour.
>>
>> HHH(DDD) does correctly report on the behavior that its
>> input specifies.
> 
> It can't. Mr Olcott said so. (See above.) You /do/ believe him, right?
> 
> 

In other words you are pretending to be so stupid that
you don't know that the word *INPUT* and the word *CALLER*
are not the exact same word?

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer