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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: Bad faith and dishonesty
Date: Sun, 1 Jun 2025 12:12:25 +0300
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On 2025-05-31 15:51:04 +0000, olcott said:
> On 5/31/2025 4:22 AM, Mikko wrote:
>> On 2025-05-30 15:32:48 +0000, olcott said:
>>
>>> On 5/30/2025 4:16 AM, Mikko wrote:
>>>> On 2025-05-29 01:37:49 +0000, Richard Damon said:
>>>>
>>>>> On 5/28/25 10:54 AM, olcott wrote:
>>>>>> On 5/28/2025 3:35 AM, Fred. Zwarts wrote:
>>>>>>> Op 27.mei.2025 om 17:31 schreef olcott:
>>>>>>>> On 5/27/2025 3:37 AM, Fred. Zwarts wrote:
>>>>>>>>> Op 27.mei.2025 om 04:22 schreef olcott:
>>>>>>>>>> On 5/26/2025 9:09 PM, Richard Damon wrote:
>>>>>>>>>>> On 5/26/25 6:05 PM, olcott wrote:
>>>>>>>>>>>> On 5/26/2025 3:44 PM, Richard Damon wrote:
>>>>>>>>>>>>> On 5/26/25 11:29 AM, olcott wrote:
>>>>>>>>>>>>>> On 5/26/2025 5:04 AM, Mikko wrote:
>>>>>>>>>>>>>>> On 2025-05-25 14:36:26 +0000, olcott said:
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> On 5/25/2025 1:21 AM, Mikko wrote:
>>>>>>>>>>>>>>>>> On 2025-05-24 01:20:18 +0000, Mr Flibble said:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> So much bad faith and dishonesty shown in this forum that myself and Peter
>>>>>>>>>>>>>>>>>> Olcott have to fight against.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> Everything here seems to be dishonesty and protests against dishonesty.
>>>>>>>>>>>>>>>>> If you could remove all dishonesty the protests woud stop, too, and
>>>>>>>>>>>>>>>>> nothing would be left.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> _DDD()
>>>>>>>>>>>>>>>> [00002192] 55 push ebp
>>>>>>>>>>>>>>>> [00002193] 8bec mov ebp,esp
>>>>>>>>>>>>>>>> [00002195] 6892210000 push 00002192
>>>>>>>>>>>>>>>> [0000219a] e833f4ffff call 000015d2 // call HHH
>>>>>>>>>>>>>>>> [0000219f] 83c404 add esp,+04
>>>>>>>>>>>>>>>> [000021a2] 5d pop ebp
>>>>>>>>>>>>>>>> [000021a3] c3 ret
>>>>>>>>>>>>>>>> Size in bytes:(0018) [000021a3]
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Then acknowledge that DDD simulated by HHH according
>>>>>>>>>>>>>>>> to the rules of the x86 language cannot possibly reach
>>>>>>>>>>>>>>>> its own "ret" instruction final halt state.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> I have never claimed that your HHH can simulate DDD to from the beginning
>>>>>>>>>>>>>>> to end.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> I am asking you to affirm that I am correct about this point.
>>>>>>>>>>>>>> DDD simulated by HHH according to the rules of the x86
>>>>>>>>>>>>>> language cannot possibly reach its own "ret" instruction
>>>>>>>>>>>>>> final halt state, thus is correctly rejected as non-halting.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> But you have to affirm first that HHH *IS* a program that does that,
>>>>>>>>>>>>> and can't be "changed" to some other program, and that DDD is
>>>>>>>>>>>>> "completed" to contain that same code.
>>>>>>>>>>>>>
>>>>>>>>>>>>> Of course, once you define that HHH is such a program,
>>>>>>>>>>>>
>>>>>>>>>>>> Unless HHH(DDD) aborts its emulation of DDD then
>>>>>>>>>>>> DDD() and HHH() never stop running proving that
>>>>>>>>>>>> the input to HHH(DDD) SPECIFIES NON-TERMINATING
>>>>>>>>>>>> BEHAVIOR THAT MUST BE ABORTED.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> But since HHH(DDD) DOES abort its emulation of DDD, it is a fact that
>>>>>>>>>>> DDD() will halt.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> *Termination analyzers PREDICT behavior dip-shit*
>>>>>>>>>> It is a tautology that every input that must be
>>>>>>>>>> aborted to prevent the infinite simulation of this
>>>>>>>>>> input DOES SPECIFY NON-HALTING BEHAVIOR.
>>>>>>>>>>
>>>>>>>>> Counter-factual. There is no need to prevent infinite simulation,
>>>>>>>>> because the input includes DDD with all functions called by DDD,
>>>>>>>>> including the code in Halt7.c that specifies the abort.
>>>>>>>>
>>>>>>>> Unless the outmost HHH aborts then none of them
>>>>>>>> abort because they all of the exact same machine code.
>>>>>>>>
>>>>>>>
>>>>>>> Only when you also change the input. Changing input from a HHH that
>>>>>>> aborts to a HHH that does not abort is changing the subject.
>>>>>>>
>>>>>>
>>>>>> It either every HHH aborts or no HHH aborts
>>>>>> because they all have the same machine code.
>>>>>
>>>>> And if every HHH aborts and returns 0, then every DDD will Halt.
>>>>>
>>>>> If no HHH aborts, then no HHH ever answers.
>>>>>
>>>>> In both cases, it is wrong.
>>>>
>>>> And if every HHH aborts and returns 1 then every DDD will halt. In
>>>> this case HHH is right. But in this case HHH is not Olcott's HHH.
>
> Abort must return 0, 1 is only returned when an input
> reaches its own final halt state.
There is no must about it. Either way the value is correct for
some inputs and wrong for other inputs.
> int main()
> {
> DDD(); // the HHH that DDD calls is not supposed to
> } // report on the behavior of its caller.
> // It is supposed to report on the behavior
> // that its input specifies.
>
>>> When DDD is correctly emulated by HHH the first four
>>> instructions of DDD are emulated. When HHH(DDD) is
>>> called from DDD then HHH emulates itself emulating DDD.
>>>
>>> No matter how many times HHH emulates itself emulating
>>> DDD the emulated DDD cannot possibly reach its "ret"
>>> instruction final halt state. This proves that DDD emulated
>>> by HHH is non-halting.
>>
>> That does not contradict what I said above.
>
> What you said above contradicts itself.
No, it does not. You cannot prove that 0 = 1 from what I said.
--
Mikko