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From: dbush <dbush.mobile@gmail.com>
Newsgroups: comp.theory,comp.ai.philosophy,sci.logic
Subject: Re: The execution trace of HHH1(DDD) shows the divergence
Date: Sat, 7 Jun 2025 10:56:55 -0400
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On 6/7/2025 10:54 AM, olcott wrote:
> On 6/7/2025 9:51 AM, dbush wrote:
>> On 6/7/2025 10:32 AM, olcott wrote:
>>> The execution trace of HHH1(DDD) shows the divergence
>>> of DDD emulated by HHH from DDD emulated by HHH1.
>>>
>>> int main()
>>> {
>>>    HHH1(DDD);
>>> }
>>>
>>> Shows that DDD emulated by HHH and DDD emulated by
>>> HHH1 diverges as soon as HHH begins emulating itself
>>> emulating DDD.
>>>
>>> *From the execution trace of HHH1(DDD) shown below*
>>> DDD emulated by HHH1              DDD emulated by HHH
>>> [00002183] push ebp               [00002183] push ebp
>>> [00002184] mov ebp,esp            [00002184] mov ebp,esp
>>> [00002186] push 00002183 ; DDD    [00002186] push 00002183 ; DDD
>>> [0000218b] call 000015c3 ; HHH    [0000218b] call 000015c3 ; HHH
>>> *HHH1 emulates DDD once then HHH emulates DDD once, these match*
>>>
>>> The next instruction of DDD that HHH emulates is at
>>> the machine address of 00002183.
>>>
>>> The next instruction of DDD that HHH1 emulates is at
>>> the machine address of 00002190.
>>
>> False.
>>
>> The next instruction of DDD that both HHH and HHH1 emulates is at the 
>> machine address of 000015c3, 
> 
> *That is not an instruction of DDD*
> *That is not an instruction of DDD*
> *That is not an instruction of DDD*
> *That is not an instruction of DDD*

In other words, you're not operating on algorithms.  And since the 
halting problem is about algorithms, what you're working on has nothing 
to do with the halting problem.

If you would just be honest about the fact that you're not working on 
the halting problem, people would stop bothering you.