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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: The execution trace of HHH1(DDD) shows the divergence
Date: Sat, 7 Jun 2025 12:10:05 -0500
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On 6/7/2025 11:37 AM, dbush wrote:
> On 6/7/2025 12:29 PM, olcott wrote:
>> On 6/7/2025 11:20 AM, dbush wrote:
>>> On 6/7/2025 12:17 PM, olcott wrote:
>>>> On 6/7/2025 11:14 AM, dbush wrote:
>>>>> On 6/7/2025 11:33 AM, olcott wrote:
>>>>>> On 6/7/2025 10:17 AM, dbush wrote:
>>>>>>> On 6/7/2025 11:12 AM, olcott wrote:
>>>>>>>> On 6/7/2025 10:08 AM, dbush wrote:
>>>>>>>>> On 6/7/2025 11:06 AM, olcott wrote:
>>>>>>>>>> On 6/7/2025 10:01 AM, dbush wrote:
>>>>>>>>>>> On 6/7/2025 10:58 AM, olcott wrote:
>>>>>>>>>>>> On 6/7/2025 9:56 AM, dbush wrote:
>>>>>>>>>>>>> On 6/7/2025 10:54 AM, olcott wrote:
>>>>>>>>>>>>>> On 6/7/2025 9:51 AM, dbush wrote:
>>>>>>>>>>>>>>> On 6/7/2025 10:32 AM, olcott wrote:
>>>>>>>>>>>>>>>> The execution trace of HHH1(DDD) shows the divergence
>>>>>>>>>>>>>>>> of DDD emulated by HHH from DDD emulated by HHH1.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> int main()
>>>>>>>>>>>>>>>> {
>>>>>>>>>>>>>>>> HHH1(DDD);
>>>>>>>>>>>>>>>> }
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Shows that DDD emulated by HHH and DDD emulated by
>>>>>>>>>>>>>>>> HHH1 diverges as soon as HHH begins emulating itself
>>>>>>>>>>>>>>>> emulating DDD.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> *From the execution trace of HHH1(DDD) shown below*
>>>>>>>>>>>>>>>> DDD emulated by HHH1 DDD emulated by HHH
>>>>>>>>>>>>>>>> [00002183] push ebp [00002183] push ebp
>>>>>>>>>>>>>>>> [00002184] mov ebp,esp [00002184] mov ebp,esp
>>>>>>>>>>>>>>>> [00002186] push 00002183 ; DDD [00002186] push
>>>>>>>>>>>>>>>> 00002183 ; DDD
>>>>>>>>>>>>>>>> [0000218b] call 000015c3 ; HHH [0000218b] call
>>>>>>>>>>>>>>>> 000015c3 ; HHH
>>>>>>>>>>>>>>>> *HHH1 emulates DDD once then HHH emulates DDD once,
>>>>>>>>>>>>>>>> these match*
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> The next instruction of DDD that HHH emulates is at
>>>>>>>>>>>>>>>> the machine address of 00002183.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> The next instruction of DDD that HHH1 emulates is at
>>>>>>>>>>>>>>>> the machine address of 00002190.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> False.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> The next instruction of DDD that both HHH and HHH1
>>>>>>>>>>>>>>> emulates is at the machine address of 000015c3,
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> *That is not an instruction of DDD*
>>>>>>>>>>>>>> *That is not an instruction of DDD*
>>>>>>>>>>>>>> *That is not an instruction of DDD*
>>>>>>>>>>>>>> *That is not an instruction of DDD*
>>>>>>>>>>>>>
>>>>>>>>>>>>> In other words, you're not operating on algorithms.
>>>>>>>>>>>>
>>>>>>>>>>>> In other words you are not actually paying any attention.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> I'm very much paying to attention to the fact that you stated
>>>>>>>>>>> that the code of the function H is not part of the input and
>>>>>>>>>>> that you're therefore not working on the halting problem.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> You say that I said things that I never said.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> You said that the instruction at address 000015c3 is not part
>>>>>>>>> of the input, which means the input to HHH is not an algorithm,
>>>>>>>>> and therefore has nothing to do with the halting problem.
>>>>>>>>>
>>>>>>>>> You really should be honest about not working on the halting
>>>>>>>>> problem.
>>>>>>>>
>>>>>>>> I never said that.
>>>>>>>>
>>>>>>>
>>>>>>> So you're saying that the input to HHH is a description/
>>>>>>> specification of algorithm DDD consisting of the fixed code of
>>>>>>> the function DDD, the fixed code of the function HHH, and the
>>>>>>> fixed code of everything that HHH calls down to the OS level, and
>>>>>>> that HHH must therefore report on the behavior of the algorithm
>>>>>>> described/ specified by its input?
>>>>>>
>>>>>> The directly executed DDD() would never stop running
>>>>>> unless HHH(DDD) aborts the simulation of its input.
>>>>>>
>>>>>> The directly executed HHH(DDD) would never stop running
>>>>>> unless HHH(DDD) aborts the simulation of its input.
>>>>>>
>>>>>> Thus conclusively proving that the input to HHH(DDD)
>>>>>
>>>>> Is not an algorithm, as you have admitted above, and therefore has
>>>>> nothing to do with the halting problem.
>>>>>
>>>>> People might actually take you seriously if you stopped lying about
>>>>> that.
>>>>
>>>> <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>>>> If simulating halt decider H correctly simulates its
>>>> input D until H correctly determines that its simulated D
>>>> would never stop running unless aborted then
>>>>
>>>> H can abort its simulation of D and correctly report that D
>>>> specifies a non-halting sequence of configurations.
>>>> </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>>>>
>>>>
>>>
>>>
>>> Irrelevent, as you're not working on the halting problem by your own
>>> admission:
>>>
>>
>> I have correctly refuted the conventional proofs of
>> the Halting Problem
>
> No you haven't, as you're not actually working on the halting problem as
> you've admitted:
>
>
This *is* the architecture of the algorithm.
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its
input D until H correctly determines that its simulated D
would never stop running unless aborted then
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer