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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Everyone on this forum besides Keith has been a damned liar about
 this point
Date: Wed, 11 Jun 2025 08:57:14 -0500
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On 6/11/2025 7:43 AM, Fred. Zwarts wrote:
> Op 10.jun.2025 om 19:27 schreef olcott:
>> On 6/10/2025 4:00 AM, Fred. Zwarts wrote:
>>> Op 09.jun.2025 om 16:43 schreef olcott:
>>>> On 6/9/2025 5:31 AM, Fred. Zwarts wrote:
>>>>> Op 09.jun.2025 om 06:15 schreef olcott:
>>>>>> On 6/8/2025 10:42 PM, dbush wrote:
>>>>>>> On 6/8/2025 11:39 PM, olcott wrote:
>>>>>>>> On 6/8/2025 10:32 PM, dbush wrote:
>>>>>>>>> On 6/8/2025 11:16 PM, olcott wrote:
>>>>>>>>>> On 6/8/2025 10:08 PM, dbush wrote:
>>>>>>>>>>> On 6/8/2025 10:50 PM, olcott wrote:
>>>>>>>>>>>> void DDD()
>>>>>>>>>>>> {
>>>>>>>>>>>>    HHH(DDD);
>>>>>>>>>>>>    return;
>>>>>>>>>>>> }
>>>>>>>>>>>>
>>>>>>>>>>>> The *input* to simulating termination analyzer HHH(DDD)
>>>>>>>>>>>
>>>>>>>>>>> No it's not, as halt deciders / termination analyzers work 
>>>>>>>>>>> with algorithms,
>>>>>>>>>>
>>>>>>>>>> That is stupidly counter-factual.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> That you think that shows that 
>>>>>>>>
>>>>>>>> My understanding is deeper than yours.
>>>>>>>> No decider ever takes any algorithm as its input.
>>>>>>>
>>>>>>> But they take a description/specification of an algorithm,
>>>>>>
>>>>>> There you go.
>>>>>>
>>>>>>> which is what is meant in this context. 
>>>>>>
>>>>>> It turns out that this detail makes a big difference.
>>>>>>
>>>>>>> And because your HHH does not work with the description/ 
>>>>>>> specification of an algorithm, by your own admission, you're not 
>>>>>>> working on the halting problem.
>>>>>>>
>>>>>>
>>>>>> HHH(DDD) takes a finite string of x86 instructions
>>>>>> that specify that HHH simulates itself simulating DDD.
>>>>>
>>>>> And HHH fails to see the specification of the x86 instructions. It 
>>>>> aborts before it can see how the program ends.
>>>>>
>>>>
>>>> This is merely a lack of sufficient technical competence
>>>> on your part. It is a verified fact that unless the outer
>>>> HHH aborts its simulation of DDD that DDD simulated by HHH
>>>> the directly executed DDD() and the directly executed HHH()
>>>> would never stop running. That you cannot directly see this
>>>> is merely your own lack of sufficient technical competence.
>>>
>>> But the abort is coded in the input. 
>>
>> I corrected you on this too many times. Stopping running
>> is not halting. Only reaching a final halt state is halting.
>> That I had to tell you this several times seems to prove
>> that you are dishonest.
> 
> You have been corrected on this many timed by many people.
> Failing to reach the final state because of a premature abort

There is no premature abort you are just stupid.

> is no 
> counter argument.
> It cannot be, because the verified fact is that the input specifies a 
> halting program, but your HHH fails to see that part of the input by the 
> premature abort.
> If you are not dishonest or stubborn, you must have a mental problem to 
> learn from your errors.
> 
> 


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer