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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic,comp.ai.philosophy
Subject: Re: HHH(DDD) is correct to reject its input as non-halting ---
 EVIDENCE THAT I AM CORRECT
Date: Mon, 16 Jun 2025 11:49:46 -0500
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In-Reply-To: <102olql$1h6pn$1@dont-email.me>

On 6/16/2025 3:49 AM, Fred. Zwarts wrote:
> Op 16.jun.2025 om 02:57 schreef olcott:
>> On 6/15/2025 6:44 PM, Richard Damon wrote:
>>> On 6/15/25 4:10 PM, olcott wrote:
>>>> void DDD()
>>>> {
>>>>    HHH(DDD);
>>>>    return;
>>>> }
>>>>
>>>> When I challenge anyone to show the details of exactly
>>>> how DDD correctly simulated by ANY simulating termination
>>>> analyzer HHH can possibly reach its own simulated "return"
>>>> statement final halt state they ignore this challenge.
>>>
>>> And it seems you don't understand that the problem is that while, 
>>> yes, if HHH does infact do a correct simulation, it will not reach a 
>>> final state, that fact only applie *IF* HHH does that, and all the 
>>> other HHHs which differ see different inputs.
>>>
>>
>> *I should have said*
>> When one or more instructions of DDD are correctly
>> simulated by ANY simulating termination analyzer HHH
>> then DDD never reaches its simulated "return" statement
>> final halt state.
>>
> 
> Why repeating this failure of HHH to reach the end of the simulation of 
> a halting program?
> We have seen that many times and it is not very interesting.
> 

In other words you have no rebuttal. Also

int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}

Every simulating termination analyzer HHH(DD) correctly
rejects its halting problem counter example input DD as
non-halting.

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer