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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic,comp.ai.philosophy
Subject: Re: HHH(DDD) is correct to reject its input as non-halting ---
 EVIDENCE THAT I AM CORRECT
Date: Fri, 20 Jun 2025 11:42:42 +0200
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Op 19.jun.2025 om 17:23 schreef olcott:
> On 6/19/2025 3:55 AM, Fred. Zwarts wrote:
>> Op 18.jun.2025 om 17:41 schreef olcott:
>>> On 6/18/2025 4:36 AM, Fred. Zwarts wrote:
>>>> Op 17.jun.2025 om 16:36 schreef olcott:
>>>>> On 6/17/2025 4:28 AM, Fred. Zwarts wrote:
>>>>>> Op 17.jun.2025 om 00:26 schreef olcott:
>>>>>>> On 6/16/2025 3:53 AM, Fred. Zwarts wrote:
>>>>>>>> Op 15.jun.2025 om 22:10 schreef olcott:
>>>>>>>>> void DDD()
>>>>>>>>> {
>>>>>>>>>    HHH(DDD);
>>>>>>>>>    return;
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>> When I challenge anyone to show the details of exactly
>>>>>>>>> how DDD correctly simulated by ANY simulating termination
>>>>>>>>> analyzer HHH can possibly reach its own simulated "return"
>>>>>>>>> statement final halt state they ignore this challenge.
>>>>>>>>
>>>>>>>> It seems very difficult for you to read.
>>>>>>>> We clearly stated that the challenge is improper.
>>>>>>>
>>>>>>> Are you too stupid to understand that dogmatic
>>>>>>> assertions that are utterly bereft of any supporting
>>>>>>> reasoning DO NOT COUNT AS REBUTTALS ???
>>>>>>
>>>>>> No, you are too stupid to realise that challenging for a recipe to 
>>>>>> draw a square circle does not count as a proof that square circles 
>>>>>> exist.
>>>>>>
>>>>>>>
>>>>>>> Claiming that I made a mistake with no ability to
>>>>>>> show this mistake is DISHONEST.
>>>>>>>
>>>>>>
>>>>>> Indeed, but irrelevant,
>>>>>
>>>>> That alternative is that you are dishonest.
>>>>> When you claim that I am wrong and have
>>>>> no ability to show how and where I am wrong
>>>>> this would seem to make you a liar.
>>>>>
>>>>> No one has ever even attempted to show the details
>>>>> of how this is not correct:
>>>>>
>>>>> void DDD()
>>>>> {
>>>>>    HHH(DDD);
>>>>>    return;
>>>>> }
>>>>>
>>>>> When one or more instructions of DDD are correctly
>>>>> simulated by ANY simulating termination analyzer HHH
>>>>> then this correctly simulated DDD never reaches its
>>>>> simulated "return" statement final halt state.
>>>>
>>>> Indeed, HHH fails to reach the end of the simulation, even though 
>>>> the end is only one cycle further from the point where it gave up 
>>>> the simulation.
>>>>
>>>
>>> That is counter-factual and over-your-head.
>>>
>>
>> No evidence presented for this claim. Dreaming again?
>> Even a beginner understands that when HHH has code to abort and halt, 
>> the simulated HHH runs one cycle behind the simulating HHH, so that 
>> when the simulating HHH aborts, the simulated HHH is only one cycle 
>> away from the same point.
> 
> Proving that you do not understand what unreachable code is.
> First year CS students and EE majors may not understand this.
> All CS graduates would understand this.

That you do not understand what I write makes it difficult for you to 
learn from your errors.
It is not that difficult. Try again and pay full attention to it.
Even a beginner understands that when HHH has code to abort and halt,
the simulated HHH runs one cycle behind the simulating HHH, so that when 
the simulating HHH aborts, the simulated HHH is only one cycle away from 
the same point.
The failure to reach that point of the simulation is a property of the 
simulator, not of the program specified in the input.

Try to learn from your errors. The resistance against learning will keep 
you stuck in your incorrect reasoning.