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From: efji <efji@efi.efji>
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Subject: =?UTF-8?Q?Re=3A_Probl=C3=A8me_du_jour=2E?=
Date: Tue, 1 Jul 2025 10:11:21 +0200
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Le 01/07/2025 à 01:32, Richard Hachel a écrit :
> e^iθ=cosθ+i.sinθ, je comprends.

e^iθ = θe^i = θ(cos(1)+i.sin(1))
e^(iθ) = cosθ +i .sinθ
merci

-- 
F.J.