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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: My reviewers think that halt deciders must report on the behavior
of their caller
Date: Sun, 6 Jul 2025 15:06:33 -0500
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In-Reply-To: <960c2417e6f691b2b12703506c207990df5b39ab@i2pn2.org>
On 7/6/2025 12:00 PM, Richard Damon wrote:
> On 7/6/25 11:19 AM, olcott wrote:
>> On 7/6/2025 6:50 AM, Richard Damon wrote:
>>> On 7/6/25 12:34 AM, olcott wrote:
>>>> On 7/5/2025 10:02 PM, Richard Damon wrote:
>>>>> On 7/5/25 10:43 PM, olcott wrote:
>>>>>> On 7/5/2025 7:44 PM, Richard Damon wrote:
>>>>>>> On 7/5/25 12:26 PM, olcott wrote:
>>>>>>>> On 7/5/2025 8:14 AM, Richard Damon wrote:
>>>>>>>>> On 7/4/25 6:11 PM, olcott wrote:
>>>>>>>>>> On 7/4/2025 3:53 PM, Richard Damon wrote:
>>>>>>>>>>> On 7/4/25 4:43 PM, olcott wrote:
>>>>>>>>>>>> On 6/3/2025 10:02 PM, dbush wrote:
>>>>>>>>>>>>> On 6/3/2025 10:58 PM, olcott wrote:
>>>>>>>>>>>>>> On 6/3/2025 9:46 PM, dbush wrote:
>>>>>>>>>>>>>>> On 6/3/2025 10:34 PM, olcott wrote:
>>>>>>>>>>>>>>>> On 6/3/2025 9:12 PM, dbush wrote:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> Given any algorithm (i.e. a fixed immutable sequence of
>>>>>>>>>>>>>>>>> instructions) X described as <X> with input Y:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> A solution to the halting problem is an algorithm H
>>>>>>>>>>>>>>>>> that computes the following mapping:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> (<X>,Y) maps to 1 if and only if X(Y) halts when
>>>>>>>>>>>>>>>>> executed directly
>>>>>>>>>>>>>>>>> (<X>,Y) maps to 0 if and only if X(Y) does not halt
>>>>>>>>>>>>>>>>> when executed directly
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Yes there is no algorithm that does that
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Excellent!
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Let The Record Show
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> That Peter Olcott
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Has *EXPLICITLY* admitted
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> That no algorithm H exists that meets the above
>>>>>>>>>>>>>>> requirements, which is precisely the theorem that the
>>>>>>>>>>>>>>> halting problem proofs prove.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> In the exact same way that there is no set of all set
>>>>>>>>>>>>>> that contain themselves. ZFC did not solve Russell's
>>>>>>>>>>>>>> Paradox as much as it showed that Russell's Paradox
>>>>>>>>>>>>>> was anchored in an incoherent foundation, now called
>>>>>>>>>>>>>> naive set theory.
>>>>>>>>>>>>>
>>>>>>>>>>>>> Which arose because the axioms of naive set theory created
>>>>>>>>>>>>> a contradiction.
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> Likewise with halt deciders that are required to report
>>>>>>>>>>>> on the behavior of directly executed Turing machines.
>>>>>>>>>>>
>>>>>>>>>>> And what is the CONTRADICTION?
>>>>>>>>>>>
>>>>>>>>>>> The result is just some things are not computable.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> The result is that there cannot possibly be
>>>>>>>>>> an *ACTUAL INPUT* that does the opposite of
>>>>>>>>>> whatever its partial halt decider decides
>>>>>>>>>> thus the HP proof fails before it begins.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> Sure there is.
>>>>>>>>>
>>>>>>>>
>>>>>>>> In order to have an honest dialogue you must pay
>>>>>>>> 100% complete attention to every single word.
>>>>>>>>
>>>>>>>> You can't just erase one of the words that I said
>>>>>>>> and then form a rebuttal on that basis.
>>>>>>>>
>>>>>>>> Directly executed Turing machines have always been
>>>>>>>> outside of the domain of every Turing machine based
>>>>>>>> decider.
>>>>>>>>
>>>>>>>>
>>>>>>>
>>>>>>> Nope.
>>>>>>>
>>>>>>> Your refusal to providee a source is your admission that you are
>>>>>>> just a liar.
>>>>>>>
>>>>>>> Remember, The DEFINITION of a Halt Deicder is that it is to be a
>>>>>>> decider that decides if the program represented by its input will
>>>>>>> halt when run.
>>>>>>>
>>>>>>
>>>>>> It has never been the program represented by its input
>>>>>> it has always been the behavior specified by its input.
>>>>>> This is the key mistake that no one noticed in 90 years.
>>>>>
>>>>> Really?
>>>>>
>>>>> In computability theory, the halting problem is the problem of
>>>>> determining, from a description of an arbitrary computer program
>>>>> and an input, whether the program will finish running, or continue
>>>>> to run forever.
>>>>>
>>>>> Sounds like the program and its representation.
>>>>>
>>>>
>>>> With pathological self-reference the directly
>>>> executed machine will not have the same
>>>> behavior as the correctly simulated machine
>>>> specification.
>>>
>>> Sure it does.
>>>
>>
>> void DDD()
>> {
>> HHH(DDD);
>> return;
>> }
>>
>> *EVERY BOT FIGURES THIS OUT ON ITS OWN*
>
> No, it just isn't smart enough to detect that you lied in your premise.
>
>> There is no way that DDD simulated by HHH (according
>> to the semantics of the C programming language)
>> can possibly reach its own "return" statement final
>> halt state.
>
> And there is no way for HHH to correctly simulate its input and return
> an answer
>
You insistence that a non-terminating input be simulated
until non-existent completion is especially nuts because
you have been told about this dozens of times.
What the F is wrong with you?
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer