| Deutsch English Français Italiano |
|
<104epf6$2ethv$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: "B. Pym" <Nobody447095@here-nor-there.org> Newsgroups: comp.lang.lisp,comp.lang.scheme Subject: Re: count symbols in a list Date: Sun, 6 Jul 2025 21:22:47 -0000 (UTC) Organization: A noiseless patient Spider Lines: 50 Message-ID: <104epf6$2ethv$1@dont-email.me> References: <104eaue$2am2p$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=iso-8859-1 Injection-Date: Sun, 06 Jul 2025 23:22:48 +0200 (CEST) Injection-Info: dont-email.me; posting-host="e9607d0181b6eedff585ea84ac51b55a"; logging-data="2586175"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19PhTKRotVV1Rdq90Xop9C6" User-Agent: XanaNews/1.18.1.6 Cancel-Lock: sha1:jqoTHVM2vdwzYRjGmYu7ol1JI7c= B. Pym wrote: > Erik Naggum wrote: > > > > I want to write a function that takes a list of symbols k and and lisp > > > expression l and counts the number of times each symbol in k occurs in > > > the lisp expression. It should return an alist binding each symbol to its > > > count. I want to do this without flattening the list before I go through > > > it looking for symbols. > > > > Look for two things in this code: How it is formatted, and how it does > > its work. (The way you have formatted your code annoys people.) Explain > > to me why this works and gives the right answer when you have ascertained > > that it does. Explain why it is efficient in both time and space. > > > > (defun count-member (symbols tree) > > (let* ((counts (loop for symbol in symbols collect (cons symbol 0))) > > Why didn't he use the simpler "mapcar" instead of "loop"? > Example: > > (mapcar (lambda(s) (cons s 0)) '(a b c)) > ===> > ((A . 0) (B . 0) (C . 0)) > > > > (lists (list tree)) > > (tail lists)) > > (dolist (list lists) > > (dolist (element list) > > (cond ((consp element) > > (setf tail (setf (cdr tail) (list element)))) > > ((member element symbols :test #'eq) > > (incf (cdr (assoc element counts :test #'eq))))))) > > counts)) > > > Testing: > > * (count-member '(w x y z) '(a x (b y y (z) z))) > > ((W . 0) (X . 1) (Y . 0) (Z . 0)) > > It only counts the top-level symbols! The testing was done under SBCL. Perhaps the function will work correctly under another version of CL. In any case, this is questionable code.