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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: Anyone that claims this is not telling the truth
Date: Sat, 17 Aug 2024 11:30:06 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <116cb41843f55511cf8fa5c2216083136e50c976@i2pn2.org>
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On 8/17/24 11:09 AM, olcott wrote:
> On 8/17/2024 10:06 AM, Richard Damon wrote:
>> On 8/17/24 10:58 AM, olcott wrote:
>>> On 8/17/2024 9:10 AM, Richard Damon wrote:
>>>> On 8/17/24 8:29 AM, olcott wrote:
>>>>> void DDD()
>>>>> {
>>>>> HHH(DDD);
>>>>> }
>>>>>
>>>>> _DDD()
>>>>> [00002172] 55 push ebp ; housekeeping
>>>>> [00002173] 8bec mov ebp,esp ; housekeeping
>>>>> [00002175] 6872210000 push 00002172 ; push DDD
>>>>> [0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
>>>>> [0000217f] 83c404 add esp,+04
>>>>> [00002182] 5d pop ebp
>>>>> [00002183] c3 ret
>>>>> Size in bytes:(0018) [00002183]
>>>>>
>>>>> *It is a basic fact that DDD emulated by HHH according to*
>>>>> *the semantics of the x86 language cannot possibly stop*
>>>>> *running unless aborted* (out of memory error excluded)
>>>>>
>>>>
>>>> No, anyone saying that the above is something that CAN be correctly
>>>> emulated by the semantics of the x86 language is just a LIAR.
>>>>
>>>
>>> You are inserting a word that I did not say.
>>>
>>
>> To say that DDD is emulated by HHH means that it must be possible to
>> validly do that act.
>>
>
> You are not going to get very far with any claim that
> emulating a sequence of x86 machine-code bytes is impossible.
>
>
How do you emulate dthe CALL HHH instruction without the code that follows?
Who is the silly one now?
And, if you say that you just use what is there, then the "input"
doesn't describe the results, and the question isn't valid, but depends
on the need to know extra information not provided.
Sorry, you are just showing your stupidity.