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Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: hitlong@yahoo.com (gharnagel) Newsgroups: sci.physics.relativity Subject: Re: Incorrect mathematical integration Date: Thu, 25 Jul 2024 23:29:43 +0000 Organization: novaBBS Message-ID: <15a62a2efad7e3485b6f622df9c78f38@www.novabbs.com> References: <EKV4LWfwyF4mvRIpW8X1iiirzQk@jntp> <UqTpLIJxvD4VcXT01kWm7g9OGtU@jntp> <v7jnc7$7jpq$1@dont-email.me> <KRDL-sfeKg0KUbMuUiMzTEhYDwk@jntp> <v7mc8d$pmhs$1@dont-email.me> <9w4qQAYIGHNeJtHg4ZR1m_Ooxo4@jntp> <v7p7bu$1cd5m$1@dont-email.me> <oEpFQDJJhcpYoGFheTTVIKntZUE@jntp> <v7qt4k$1obhi$1@dont-email.me> <E7KdnZQ2kcpMMz_7nZ2dnZfqnPadnZ2d@giganews.com> <b4WXAi8P2nvCwUATxx84m5e52Ro@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Info: i2pn2.org; logging-data="362607"; mail-complaints-to="usenet@i2pn2.org"; posting-account="p+/k+WRPC4XqxRx3JUZcWF5fRnK/u/hzv6aL21GRPZM"; User-Agent: Rocksolid Light X-Spam-Checker-Version: SpamAssassin 4.0.0 X-Rslight-Site: $2y$10$0h7FQ.3kigCDOw4zUR.rPObx0wVYvoENKQvSQLwf34aOxVO7d99Ea X-Rslight-Posting-User: 47dad9ee83da8658a9a980eb24d2d25075d9b155 Bytes: 2419 Lines: 36 On Thu, 25 Jul 2024 20:30:09 +0000, Richard Hachel wrote: > > In the case you are proposing, there is no contraction of the distances, > because the particle is heading TOWARDS its receptor. > > The equation is no longer D'=D.sqrt(1-Vo²/c²) and to believe this is to > fall into the trap of ease, but D'=D.sqrt[(1+Vo/c)/ (1-Vo/c)] since > cosµ=-1. You are conflating Doppler effect with length contraction. LC is ALWAYS D'=D.sqrt(1-Vo²/c²). > For the particle the distance to travel (or rather that the receiver > travels towards it) is extraordinarily greater than in the laboratory > reference frame. > > R.H. Your assertion is in violent disagreement with the LTE: dx' = gamma(dx - vdt) dt' = gamma(dt - vdx) For an object stationary in the unprimed frame, dx = 0: dx' = gamma(-vdt) dt' = gamma(dt) v' = dx'/dt' = -v For an object moving at v in the unprimed frame, dx' = 0 v = dx/dt = v. There is no "extraordinarily greater" speed in either frame. This is true in Galilean motion also. Galileo described it perfectly with his ship and dock example and blows your assertion out of the water, so to speak.