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Date: Sun, 4 Aug 2024 14:57:06 +0200 Mime-Version: 1.0 User-Agent: Mozilla Thunderbird Subject: Re: Relativistic aberration Newsgroups: sci.physics.relativity References: <QsysQnpetTSlB_zDsjAhnCKqnbg@jntp> <v8cgia$1e4s9$1@dont-email.me> <O-L1WgU1eCsz14Wrc6D7tpNPV7s@jntp> <v8fkn6$23nee$1@dont-email.me> <FS7BRIsxO-_X20VxXPebSsjPIt4@jntp> <v8gpr4$2c66e$1@dont-email.me> <1r17YwSTuu_yFwJ8Mj7O-umZb_M@jntp> <v8jd83$2vsa3$1@dont-email.me> <aGJtGFi-pcZdeYKlbLrP7fJkFGw@jntp> <v8m3tk$3k7em$1@dont-email.me> <n6nnyNLQR1tXDC_uShX3k3bxE5g@jntp> <v8ntdq$2b3b$1@dont-email.me> Content-Language: pl From: Maciej Wozniak <mlwozniak@wp.pl> In-Reply-To: <v8ntdq$2b3b$1@dont-email.me> Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Lines: 63 Path: ...!weretis.net!feeder9.news.weretis.net!usenet.blueworldhosting.com!diablo1.usenet.blueworldhosting.com!tr1.iad1.usenetexpress.com!feeder.usenetexpress.com!tr2.eu1.usenetexpress.com!news.newsdemon.com!not-for-mail Nntp-Posting-Date: Sun, 04 Aug 2024 12:57:05 +0000 X-Received-Bytes: 3130 X-Complaints-To: abuse@newsdemon.com Organization: NewsDemon - www.newsdemon.com Message-Id: <17e887d977272153$96453$546728$c2565adb@news.newsdemon.com> Bytes: 3536 W dniu 04.08.2024 o 14:50, Paul.B.Andersen pisze: > Den 03.08.2024 23:40, skrev Richard Hachel: >> Le 03/08/2024 à 22:28, "Paul.B.Andersen" a écrit : >>> >>> E(x,y,z,t) = (12000 ly, 9000 ly, 0 ly, -15000.0 y) >>> t is when the light left the telescope, now = 0 y >>> >>> Let us assume that, in accordance with convention, >>> the x-axis is pointing toward the vernal point Epoch J200, >>> and the x-y plane is the ecliptic plane. The z-axis will >>> then point toward the ecliptic north pole. >>> >>> The RA is then arctan(9000/12000) = 37⁰ >>> The DEC = 0⁰ >>> The distance d = √(x² + y² + z²) = 15000 ly >>> >>> Since the rocket is moving along the x-axis' >>> the angle velocity - (direction to star) = 37⁰, >>> the RA in the rocket frame will due to aberration be 12.7⁰ >>> the DEC = 0. >>> Since the rocket and the Earth are colocated at the time of reception, >>> they will obviously receive the same light which was emitted from >>> the star 15000 years ago. >>> That means that the distance in the Rocket frame must be 15000 ly. >>> >>> Simple geometry will give: >>> x' = 15000⋅cos(12.7⁰) ly = 14633 ly >>> y' = 15000⋅sin(12.7⁰) ly = 3297 ly >>> z' = 0 ly >>> t' = -15000/c year = -15000 year >>> >>> E '= (14633 ly, 3297 ly, 0 ly, -15000 y) >> >> ? ? ? >> <http://news2.nemoweb.net/jntp?n6nnyNLQR1tXDC_uShX3k3bxE5g@jntp/Data.Media:1> >> >> >> But what are you talking about? ? ? >> >> You're talking nonsense!!! >> >> Your thing IS nonsense! >> >> How do you want the object to be at the same distance in both frames >> of reference? ? ? > > This is about what the observers SEE in their telescopes. > > They are co-located when they receive the light from the supernova, > so they obviously both see the star as it goes supernova. > > Since earth observers have _measured_ (via parallax ?) the distance > to the star to be 15000 ly, and the speed of light is c in the > Earth frame, the earth observer can deduce that the light must > have left the star 15000 years ago. Again common sense prejudices, refuted by your idiot gurus with their "inflation" "discovery". Your poor halfbrain is still polluted with them, they didn't brainwash you enough.