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Subject: Re: Langevin's paradox again
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Date: Thu, 11 Jul 24 12:49:49 +0000
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From: Richard Hachel <r.hachel@tiscali.fr>
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Le 11/07/2024 à 14:36, "Paul.B.Andersen" a écrit :
> 
> You could say:
> "When both twins are inertial each twin will measure the other
>   twin's  clock to beat slower than his own clock, both on
>   the outward and return journey".
> 
> Which would make your statement above partly right.
> 
> But what happens when twin B is accelerating makes all the difference.

I think you still don't understand what I mean when I talk about internal 
chronotropy,
and measuring what is actually written on the watches.
As long as you don't make the effort (because the problem is on your 
side), you don't make the effort to understand me, we won't get there.
You criticize a theory that you don't understand.
YOU confuse two things, and thus show that you do not understand them.
I beg you not to confuse them again.
I beg you to understand that internal chronotropy of watches does not mean 
measuring the passage of time on watches.
It is FUNDAMENTAL to understand this.
If you don't understand this, you will never be able to understand how the 
theory of relativity works and you will teach a shaky or even false theory 
in places.

R.H.