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Path: ...!feeds.phibee-telecom.net!2.eu.feeder.erje.net!feeder.erje.net!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: liz@poppyrecords.invalid.invalid (Liz Tuddenham) Newsgroups: sci.electronics.design Subject: Re: LTSpice model for a SiC MOSFET Date: Thu, 22 May 2025 09:44:30 +0100 Organization: Poppy Records Lines: 26 Message-ID: <1rcqaf8.b7hc3i1j6cugoN%liz@poppyrecords.invalid.invalid> References: <100c4og$t4lo$1@dont-email.me> <1rcl8ui.1xbo3q4bshnscN%liz@poppyrecords.invalid.invalid> <1dnm2k12d94ciunjpv2aavhb1v4peg9h60@4ax.com> X-Trace: individual.net RPWOUvZmHnq1TViTB1wD5QRbh2FXJhyE5Pr1PMetd3LPBLUep3 X-Orig-Path: liz Cancel-Lock: sha1:puPgV+/4iFBeVNXGpS9561bhipk= sha256:+q/2xnZg9/tewifWpzMJjDA1Qr6DZPBV1WCi6kiF/78= User-Agent: MacSOUP/2.4.6 Bytes: 1679 john larkin <jl@glen--canyon.com> wrote: [...] > Going from 1KV to 3.3v has interesting possibilities. The easy way is > a resistor and a zener. Efficiency about 0.3%. Roughly 1W dissipation per mA , so if the current requirement isn't too high, that is probably the most straightforward system with very little to go wrong. > More efficient would be a resistor and a zener and then a buck > switcher. 5% maybe. That's a lot of extra complication for very little improvement, the resistor still has to carry the full load current. For a cult market you could use an 807 and tap the 3.3v off the cathode bias resistor. (or better still, rectify the heater supply and use a linear regulator but don't tell the customer). -- ~ Liz Tuddenham ~ (Remove the ".invalid"s and add ".co.uk" to reply) www.poppyrecords.co.uk