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X-Received: by 2002:a37:655:0:b0:759:4c9a:1aa5 with SMTP id 82-20020a370655000000b007594c9a1aa5mr70995qkg.2.1686307020625; Fri, 09 Jun 2023 03:37:00 -0700 (PDT) X-Received: by 2002:a25:abe2:0:b0:b9d:b6cd:2dfd with SMTP id v89-20020a25abe2000000b00b9db6cd2dfdmr562491ybi.8.1686307020393; Fri, 09 Jun 2023 03:37:00 -0700 (PDT) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Fri, 9 Jun 2023 03:37:00 -0700 (PDT) In-Reply-To: <B5I0508lkzA97sBVz6Z4qL0S2hs@jntp> Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:997a:f528:4244:3d16; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:997a:f528:4244:3d16 References: <stDECQg9WR9Evb6RUW3-0FFOlek@jntp> <7e7733d3-20c2-41f9-aa12-254ff48844f4n@googlegroups.com> <u5sl37$1h802$1@dont-email.me> <cf7dbee4-6d32-4f0e-8b75-081cadfba0a7n@googlegroups.com> <7NBboA_mGQPKzsXkP5IyvxaOCoo@jntp> <4d5decfe-63c3-4423-9a31-5e6c33eac43fn@googlegroups.com> <u5tkg5$1l1ja$1@dont-email.me> <a76ee714-379b-4785-ba13-9577f2f6d06fn@googlegroups.com> <B5I0508lkzA97sBVz6Z4qL0S2hs@jntp> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <2012182a-285c-494f-8138-99a8da12ea4fn@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_De_la_relativit=C3=A9_des_distances?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Fri, 09 Jun 2023 10:37:00 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2743 Lines: 17 Le vendredi 9 juin 2023 =C3=A0 11:57:27 UTC+2, Richard Hachel a =C3=A9crit= =C2=A0: > Si tu pars sur le principe qu'il n'y a pas d'int=C3=A9r=C3=AAt =C3=A0 fai= re des=20 > transformations entre syst=C3=A8mes de coordonn=C3=A9es en relativit=C3= =A9 restreinte,=20 > je vois pas ce qu'il te reste =C3=A0 traiter. Salut Richard ! Quand on prend des =C3=A9v=C3=A9nements simultan=C3=A9s dan= s un r=C3=A9f=C3=A9rentiel, on obtient la transformation d=E2=80=99une fig= ure d=E2=80=99un r=C3=A9f=C3=A9rentiel =C3=A0 un autre, ce qui est le propr= e d=E2=80=99une transformation ponctuelle. La transformation de Lorentz du = r=C3=A9f=C3=A9rentiel R =C3=A0 R=E2=80=99 donne pour un segment L=E2=80=99 = =3D k L; k =C3=A9tant l=E2=80=99inverse du coefficient de Lorentz. Lors du = passage de R=E2=80=99 a R, on obtient L =3D k L=E2=80=99;=20 d=E2=80=99o=C3=B9 L =3D k^2 L. Cherchez l=E2=80=99erreur!=20 Ce que j=E2=80=99ai donc trait=C3=A9 c=E2=80=99est une transformation T qui= donne T o T^-1 (L) =3D L, c=E2=80=99est =C3=A0 dire telle que L =3D k^2 L,= soit k=3D 1. Et cette transformation n=E2=80=99est pas celle de Lorentz.