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From: Michael S <already5chosen@yahoo.com>
Newsgroups: comp.lang.c++,comp.lang.c
Subject: Re: Threads across programming languages
Date: Fri, 3 May 2024 18:01:02 +0300
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On Fri, 3 May 2024 13:23:13 +0200
Bonita Montero <Bonita.Montero@gmail.com> wrote:

> Am 03.05.2024 um 11:18 schrieb David Brown:
> > On 03/05/2024 09:58, Bonita Montero wrote: =20
> >> Am 03.05.2024 um 09:38 schrieb David Brown:
> >> =20
> >>> No it is not.=A0 C-style functions (or C++ functions for that
> >>> matter) are not objects, and do not have calling operators.
> >>> Built-in operators do not belong to a type, in the way that class
> >>> operators do. =20
> >>
> >> You can assign a C-style function pointer to an auto
> >> function-object. =20
> >=20
> > A C-style function /pointer/ is an object.=A0 A C-style /function/ is
> > not. Do you understand the difference? =20
>=20
> Practically there isn't a difference.
>

For C, I agree, mostly because C has no nested functions.=20
For C++ (after C++11) I am less sure, because of lambdas with
non-empty captures.