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From: Kaz Kylheku <643-408-1753@kylheku.com>
Newsgroups: comp.lang.c
Subject: Re: technology discussion =?UTF-8?Q?=E2=86=92?= does the world need
 a "new" C ?
Date: Wed, 10 Jul 2024 11:27:09 -0000 (UTC)
Organization: A noiseless patient Spider
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On 2024-07-10, Lawrence D'Oliveiro <ldo@nz.invalid> wrote:
> On Sat, 06 Jul 2024 15:23:47 -0700, Keith Thompson wrote:
>
>> Lawrence D'Oliveiro <ldo@nz.invalid> writes:
>>
>>> On Fri, 05 Jul 2024 11:46:38 -0700, Keith Thompson wrote:
>>>
>>>> No, arrays are not pointers.
>>>
>>> Except array indexing is designed to be indistinguishable from pointer
>>> arithmetic.
>> 
>> No, arrays are not pointers.
>
> Can you point out any situation where this construct
>
>     &a[b]
>
> might be valid, but this
>
>     (a + b)
>
> (with the same declarations of “a” and “b”) might not?

Miller Genuine Daft at work again.

a[b] /means/ *(a + (b)) so your reasoning is circular.

Arrays are not pointers. Given arrays a and b of equal size:

- sizeof a is not sizeof &[0] other than by coincidence

- &a is not &a[0] -- different type

- a = b is invalid -- arrays are not modifiable lvalues

- arrays cannot be passed to functions nor returned;
  pointers can.

- int (f[3])(void) { }, function returning array of 3 int,
  is a constraint violation.
  
-- 
TXR Programming Language: http://nongnu.org/txr
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