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From: Michael S <already5chosen@yahoo.com>
Newsgroups: comp.arch
Subject: Re: Continuations
Date: Thu, 18 Jul 2024 22:24:52 +0300
Organization: A noiseless patient Spider
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On Thu, 18 Jul 2024 18:48:45 -0000 (UTC)
Thomas Koenig <tkoenig@netcologne.de> wrote:

> Michael S <already5chosen@yahoo.com> schrieb:
> > On Thu, 18 Jul 2024 17:06:52 -0000 (UTC)
> > Thomas Koenig <tkoenig@netcologne.de> wrote:  
> >> It does work far away from the equilibrium (which is the point).  
> >
> > But how far?
> > Does it work for EA/RT outside of, say [-10:+12] ?  
> 
> Ea is almost always positive; if if was negative, it would mean that
> a reaction is is slowed down by increasing temperature (and by this
> don't mean the reverse reaction).  If you see that in data, that
> means that the Arrhenius model is not applicable because there is
> in fact no activation energy to overcome, that something strange
> happens in thermodynamics (say, you get solid precipitation of
> one component at a certain temperature) or that some there are
> some intermediate steps which are not described in the model.
> 
> And to make sense, -Ea/(RT) is always less then zero.  Reasonable
> example: Ea = 30 kJ/mol, R=8.314, T=600 K gives you -6.01 as the
> argument of the exponent, so the term is then ~ 0.002444 .