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Subject: Re: Want to prove =?UTF-8?B?RT1tY8KyPyBVbml2ZXJzaXR5IGxhYnMgc2hvdWxkIHRy?=
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Date: Mon, 18 Nov 2024 03:21:07 +0000
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On Sun, 17 Nov 2024 23:34:24 +0000, rhertz wrote:

> Obviously, there is a problem understanding the proposed experiment.
>
> *******************************************************************
> 1) ABOUT THE DIFFERENTIAL ELECTROMAGNETIC BALANCE (there are other
> means):
>
> I propose to use TWO DEB, similar to the one of which I posted a link:
>
> Homemade Microgram Electrobalance
>
> https://www.erowid.org/archive/rhodium/chemistry/equipment/scale.html
>
> The output of the two sensors are connected to electronics, which can
> REST, filter and process the electrical output of the EB. The result,
> once calibrated to be ZERO while the laser is off, will be a LINEAR
> relation between weight difference and voltage, in the order of
> nanograms.
>
> The DEB will be working in a vacuum, with a Faraday-like dome, and
> floating on a mercury bed (to filter vibrations, noise and EM
> interferences. It also will be compensated in temperature by means to
> cool it off and measure the heat excess that's eliminated.
>
> *******************************************************************
>
> 2) ABOUT THE CAVITY:
>
> It has not to be a perfect sphere. On the contrary.
> Imagine that you take 2 mg of aluminum foil and build a case with it,
> having dimensions of about 1,000 cm³. The inner coating, made of highly
> reflective material, has artificial irregularities much narrower than
> the laser wavelength (green, 550 nm), such that the laser beam (1 mm
> radius) spread all over the interior of the cavity, with a very small
> percentage escaping through the 2 mm orifice.
>
> If necessary, make the external laser device to spatially oscillate
> slowly a little amount (by mechanical means) to assure that the beam is
> hitting different spots within the cavity. That will spread the
> radiation all over inside its volume.
>
> Two identical cavities are built, being each one placed on the DEB.
> Their weight (a few grams) will be subtracted from their electrical
> outputs, so that (in perfect balance and equilibrium), the output will
> read 0.000 nanograms.
>
> *******************************************************************
>
> 3) ABOUT THE DIFFERENT LOSSES:
>
> Every deviation from a perfect setup, due to different losses and
> perturbations, will be measured and considered in the final result.
>
> The differential output signal [linear function of the weight
> difference] will be processed to filter NOISE, including the electrical
> noise (in the order of nanovolts) generated by the EM mechanisms.
>
> ******************************************************************
>
> 4) ABOUT THE ACCUMULATION OF ENERGY INSIDE THE CAVITY 1:
>
> If the reflected laser beams are almost 100% reflected and only a very
> small fraction of energy dissipates as heat (0.001%), the energy will
> accumulate linearly with time:
>
> 5 W x 1 Hr = 18,000 Joules per hour
>
> By m=E/c², it represents 2.0E-10 gram of mass per hour.
>
> In 72 hours, the accumulated energy within the cavity represents
> 1.44E-08 gram of mass.
>
> This value of mass represents 0.1398 microNewtons in 72 hours.
>
> Such values are perfectly in the range of measurement for current
> technologies (state of the art).
>
> Check my second link of a lab balance ($10,000), capable of measuring
> weight (mass equivalence) in the order of 0.1 microNewtons.
>
> Imagine what can be built investing $ 100,000 or $ 1,000,000 in a
> qualified lab.
>
> *****************************************************************
>
> This experiment allows to probe/disprove E = mc² in the real world, not
> in the fairy land of the quantum/atomic world.

Your experiment is absurdly impractical. A case 1,000 cm³ in volume
would (if cubical) be 10 cm on a side. Light would be expected to
bounce off the interior surfaces about 3e9 times a second. Even if the
reflectivity were 99.999% (*IMPOSSIBLE* to achieve with diffuse
reflectors) then 3 percent of the light's energy will be lost each
second to absorption, heating up the chamber walls. It would take only
a few minutes for effectively all of the energy of a pulse of light to
be dissipated as heat. But you are not using a _pulse_ of light. You
propose using a 5 W continuous beam, meaning that over the long run,
the chamber will be heated up by 5 watts of power, or 18 KJ per hour.

In other words, your 2 mg chamber is going to get pretty warm very
fast.

Warm objects radiate heat energy. Radiated heat carries momentum.
The momentum of the radiated heat will distort your weight
measurements.