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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.logic
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
Date: Sun, 15 Dec 2024 07:52:11 -0500
Organization: i2pn2 (i2pn.org)
Message-ID: <226bc62e19a54dd1daece7527c572801b6fd9d39@i2pn2.org>
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On 12/15/24 6:08 AM, WM wrote:
> On 15.12.2024 11:50, Mikko wrote:
>> On 2024-12-14 08:42:37 +0000, WM said:
>>
>>> On 14.12.2024 09:30, Mikko wrote:
>>>> On 2024-12-13 10:28:44 +0000, WM said:
>>>>
>>>>> On 13.12.2024 10:46, Mikko wrote:
>>>>>
>>>>>> Between any two intervals there is space and that space contains 
>>>>>> other
>>>>>> intervals.
>>>>>
>>>>> No. Starting from a point in the complement the cursor will hit a 
>>>>> first interval. This is true for all visible intervals.
>>>>
>>>> False. From a point that is not a part of an interval no interval is 
>>>> the
>>>> nearest one because another interval is nearer.
>>>
>>> IF ALL intervals and their endpoints are existing as invariable 
>>> points on the real line this cannot happen.
>>
>> It can. Your { [q_n - sqrt(2)/2^n, q_n + sqrt(2)/2^n] | n = 1, 2, 
>> 3, ... }
>> is one such set.
> 
> That is nothing but an unfounded claim. In actual infinity of set theory 
> all intervals and their endpoints are existing as invariable points from 
> the beginning of the cursor's motion.
> 
> Regards, WM
> 
> 

So? The problem is the cursor can't move without immediately hitting 
segments, none of which are "next" because they are dense.