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Subject: Re: The problem of relativistic synchronisation
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Date: Sun, 01 Sep 24 20:29:23 +0000
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From: Richard Hachel <r.hachel@tiscali.fr>
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Le 01/09/2024 à 19:41, "Paul.B.Andersen" a écrit :
> Den 01.09.2024 16:13, skrev Richard Hachel:

>>>> AB (at rest) = 3.10^8m
>>>> A'B' (at rest) = 3.10^8m
>>>>
>>>> v=0.8c 
>>>> tA(e2)= ?

> tA(e2)=0.75 sec

> Chicken!

 No YOU chicken !

 tA (e1)= 0
 tA'(e1)= 0
 tA (e2)= 0.75 

 But now, we have to go further. Do you want to remain a chicken?
> No.
Why, Paul?
> Because I don't want to be a chicken anymore. I want to be a brave man.

OK, Paul.

So we're going to continue, because it's very important.

A sees the segment AB coming towards him, and when A' crosses A, which is 
event e1, A starts his watch. tA(e1)=0

Then A observes that B' is approaching him at high speed, and stops his 
watch when B crosses him, this is event e2, and we note tA(e2)=0.75.

There is an interval of 0.75 seconds between e1 and e2.

But, however, Paul is a chicken. And he's going to run away (prophecy of 
Nostradamus).
"Great King Hachel speak usenet
Afraid chicken run away".

For 0.75 seconds, B' rushes toward A.

Two questions that today represent two of the biggest questions in the 
entire existence of sci.physics?relativity

1. At what apparent (i.e. APPARENT) speed does A apprehend B' rushing 
toward him?

Chicken!

2. What is the apparent distance traveled by B' during the interval noted 
by the watch?

Chicken! Chicken!

R.H.