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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: HHH(DDD) computes the mapping from its input to HHH emulating
 itself emulating DDD --- anyone that says otherwise is a liar
Date: Thu, 21 Nov 2024 21:55:25 -0500
Organization: i2pn2 (i2pn.org)
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On 11/21/24 4:19 PM, olcott wrote:
> On 11/21/2024 3:11 PM, joes wrote:
>> Am Thu, 21 Nov 2024 09:19:03 -0600 schrieb olcott:
>>> On 11/20/2024 10:00 PM, Richard Damon wrote:
>>>> On 11/20/24 9:57 PM, olcott wrote:
>>>>> On 11/20/2024 5:51 PM, Richard Damon wrote:
>>>>>> On 11/20/24 5:03 PM, olcott wrote:
>>>>>>> On 11/20/2024 3:53 AM, Mikko wrote:
>>>>>>>> On 2024-11-20 03:23:12 +0000, olcott said:
>>>>>>>>> On 11/19/2024 4:12 AM, Mikko wrote:
>>>>>>>>>> On 2024-11-18 20:42:02 +0000, olcott said:
>>>>>>>>>>> On 11/18/2024 3:41 AM, Mikko wrote:
>>>>>>>>>>>> The "the mapping" on the subject line is not correct. The
>>>>>>>>>>>> subject line does not specify which mapping and there is no
>>>>>>>>>>>> larger context that could specify that. Therefore it should be
>>>>>>>>>>>> "a mapping".
>>>>>>>>>>>> On 2024-11-17 18:36:17 +0000, olcott said:
>>
>>>>> My code is one example of the infinite set of every possible HHH that
>>>>> emulates DDD according to the semantics of the x86 language.
>> Like all of them, it is unable to simulate DDD to its undeniable halting
>> state.
>>
> 
> In your case you may simply not even understand what
> infinite recursion is, thus cannot see the isomorphism.
> 
>>>> But it gets the wrong answer for the halting problem, as DDD dpes halt.
>>> DDD emulated by HHH does not halt.
>> Whatever. DDD halts and HHH should return that.
> 
> IT IS NOT THE SAME INSTANCE OF DDD.
> HHH is reporting on the behavior of its INPUT.
> 
> HHH is not reporting on the behavior of some other
> different DDD instance that behaves differently.

Then there is something wrong with your theory of computation, as one 
essental part of the normal theory is that all copies of the same 
program, need to behave identically when given the same input.

I guess thios just proves how broken your logic is.

> 
> 
>> I can make a "decider" this way: it simulates no steps at all and returns
>> that all inputs halt when simulated by it.
>>
>>> Are you a fake Christian?
>> I am a fake Scientologist.
> 
> That may be the correct Scientologist to be.
> 
>