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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: The philosophy of computation reformulates existing ideas on a
 new basis ---x86 code is a liar?
Date: Fri, 15 Nov 2024 11:23:21 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Thu, 14 Nov 2024 17:53:38 -0600 schrieb olcott:
> On 11/14/2024 3:09 AM, Mikko wrote:
>> On 2024-11-13 23:11:30 +0000, olcott said:
>>> On 11/13/2024 4:58 AM, Mikko wrote:
>>>> On 2024-11-12 13:58:03 +0000, olcott said:
>>>>> On 11/12/2024 1:12 AM, joes wrote:
>>>>>> Am Mon, 11 Nov 2024 10:35:57 -0600 schrieb olcott:
>>>>>>> On 11/11/2024 10:25 AM, joes wrote:
>>>>>>>> Am Mon, 11 Nov 2024 08:58:02 -0600 schrieb olcott:
>>>>>>>>> On 11/11/2024 4:54 AM, Mikko wrote:
>>>>>>>>>> On 2024-11-09 14:36:07 +0000, olcott said:
>>>>>>>>>>> On 11/9/2024 7:53 AM, Mikko wrote:
>>>>>>
>>>>>>>>> The actual computation itself does involve HHH emulating itself
>>>>>>>>> emulating DDD. To simply pretend that this does not occur seems
>>>>>>>>> dishonest.
>>>>>>>> Which is what you are doing: you pretend that DDD calls some
>>>>>>>> other HHH that doesn’t abort.
>>>>>>> DDD emulated by HHH does not reach its "return" instruction final
>>>>>>> halt state whether HHH aborts its emulation or not.
>>>>>> When DDD calls a simulator that aborts, that simulator returns to
>>>>>> DDD, which then halts.
>>>>> It is not the same DDD as the DDD under test.

How do they differ?

>>>> If the DDD under the test is not the same as DDD then the test is
>>>> performed incorrectly and the test result is not valid.
>>> The DDD under test IS THE INPUT DDD
>> I agree that there is only one DDD but above you said otherwise.
> DDD emulated by HHH emulates itself emulating DDD and DDD emulated by
> HHH1 *DOES NOT DO THAT*
Those are the same DDD. The difference lies with the simulators.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.