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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: 2N=E
Date: Sun, 3 Nov 2024 07:13:48 -0500
Organization: i2pn2 (i2pn.org)
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On 11/3/24 6:49 AM, WM wrote:
> On 03.11.2024 01:17, Richard Damon wrote:
>> On 11/2/24 5:34 PM, WM wrote:
> 
>> Remember, 2 times any Natural Number is a Natural Number, provable by 
>> mathematics.
> 
> Every doubled interval gets larger. (0, ω)*2 = (0, ω*2).

Nope, as no element of (0, ω) when doubled exceeds ω, as all were 
finite, and twice a finite number is finite.

Note, you can't multiply an interval by a value, you double the elements 
of the interval. It might work for finite intervals, but not for 
infinite intervals.

> 
>>> Every interval (0, n) is finite because n is finite. But for dark 
>>> numbers n this cannot be seen. The dark realm appears as infinite. It 
>>> cannot be counted through.
>>
>> And thus is not finite.
> 
> Its numbers are finite as we see when a dark number becomes visible. ω 
> is the first infinite number by definition. ω - 1 is finite but lies in 
> the dark realm and therefore cannot be counted to. It appears as if it 
> was infinite.
> 

If a dark number can become visible, then it was never dark, and your 
set was never complete.

ω - 1 is NOT "finte" but undefined in the base mode of Trans-Finite 
Numbers, just as 0-1 isn't defined in the set of Numbers 0, 1, 2, ...

Your "Dark Numbers" are just the impossiblitlies your broken logic 
create to try to avoid showing their flaws.

> Regards, WM
>