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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1
Date: Thu, 27 Mar 2025 21:56:28 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Thu, 27 Mar 2025 13:10:46 -0500 schrieb olcott:
> On 3/27/2025 6:02 AM, Richard Damon wrote:
>> On 3/26/25 11:47 PM, olcott wrote:
>>> On 3/26/2025 10:28 PM, Richard Damon wrote:
>>>> On 3/26/25 11:09 PM, olcott wrote:
>>>>> On 3/26/2025 8:22 PM, Richard Damon wrote:

>>>>>> Non-Halting is that the machine won't reach its final staste even
>>>>>> if an unbounded number of steps are emulated. Since HHH doesn't do
>>>>>> that, it isn't showing non-halting.
>>>>> DDD emulated by any HHH will never reach its final state in an
>>>>> unbounded number of steps.
>>>> But DDD emulated by an actually correct emulator will,
>>> If you were not intentionally persisting in a lie you would
>>> acknowledge the dead obvious that DDD emulated by HHH according to the
>>> semantics of the x86 language cannot possibly correctly reach its
>>> final halt state.
Yes, HHH is not a correct simulator.

>> And if you were not intentionally persisting in a lie, you would admit
>> that your HHH doesn't do that, as it stops before it finishes.
>> 
>> 
>>> The behavior that DDD specifies to HHH <is> the behavior that it must
>>> report on.
DDD doesn't specify anything different *to* HHH. It is just the same code.

>> Which, by the definition, is the behavior of the directly executed DDD,
> That is counter-factual.
> The behavior IS WHAT IT IS and that includes recursive emulation.
Yes, HHH is counter to the definition - i.e. wrong. It is not
automatically correct whatever it does.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.