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Date: Mon, 5 Aug 2024 08:49:44 -0500
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Subject: Re: Who knows that DDD correctly simulated by HHH cannot possibly
 reach its own return instruction final state?
Newsgroups: comp.theory
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From: olcott <NoOne@NoWhere.com>
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On 8/5/2024 2:39 AM, Mikko wrote:
> On 2024-08-04 18:59:03 +0000, olcott said:
> 
>> On 8/4/2024 1:51 PM, Richard Damon wrote:
>>> On 8/4/24 9:53 AM, olcott wrote:
>>>> On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
>>>>> Op 03.aug.2024 om 18:35 schreef olcott:
>>>>  >>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
>>>>>> reach their own "return" instruction final state.
>>>>>>
>>>>>> So you are saying that the infinite one does?
>>>>>>
>>>>>
>>>>> Dreaming again of HHH that does not abort? Dreams are no substitute 
>>>>> for facts.
>>>>> The HHH that aborts and halts, halts. A tautology.
>>>>
>>>> void DDD()
>>>> {
>>>>    HHH(DDD);
>>>>    return;
>>>> }
>>>>
>>>> That is the right answer to the wrong question.
>>>> I am asking whether or not DDD emulated by HHH
>>>> reaches its "return" instruction.
>>>
>>> But the "DDD emulated by HHH" is the program DDD above,
>>
>> When I say DDD emulated by HHH I mean at any level of
>> emulation and not and direct execution.
> 
> If you mean anything other than what the words mean you wihout
> a definition in the beginning of the same message then it is
> not reasonable to expect anyone to understand what you mean.
> Instead people may think that you mean what you say or that
> you don't know what you are saying.
> 

If you don't understand what the word "emulate" means look it up.

DDD (above) cannot possibly reach its own "return" instruction halt
state when its machine code is correctly emulated by HHH.

-- 
Copyright 2024 Olcott

"Talent hits a target no one else can hit;
  Genius hits a target no one else can see."
  Arthur Schopenhauer