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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: ChatGPT refutes the key rebuttal of my work
Date: Wed, 16 Oct 2024 18:06:40 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <45e53fc60dfc649ed11a8704e5d860766dd88955@i2pn2.org>
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Am Wed, 16 Oct 2024 12:46:01 -0500 schrieb olcott:
> On 10/16/2024 12:27 PM, joes wrote:
>> Am Wed, 16 Oct 2024 10:39:21 -0500 schrieb olcott:
>>> On 10/16/2024 9:45 AM, joes wrote:
>>>> Am Wed, 16 Oct 2024 09:11:22 -0500 schrieb olcott:
>>>>> On 10/16/2024 9:01 AM, joes wrote:
>>>>>> Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:
>>>>>>> On 10/16/2024 1:33 AM, joes wrote:
>>>>>>>> Am Tue, 15 Oct 2024 16:51:15 -0500 schrieb olcott:
>>>>>>>>> On 10/15/2024 4:24 PM, joes wrote:
>> 
>>>>>>> Terminating C functions must reach their "return" statement.
>>>>>> Which DDD does.
>>>>> THIS IS ALSO THE INDUSTRY STANDARD DEFINITION It is stipulated that
>>>>> *correct_x86_emulation* means that a finite string of x86
>>>>> instructions is emulated according to the semantics of the x86
>>>>> language beginning with the first bytes of this string.
>>>> You are not simulating the given program, but a version that differs
>>>> in the abort check.
>>> HHH is correctly emulating (not simulating) the x86 language finite
>>> string of DDD including emulating the finite string of itself
>>> emulating the finite string of DDD up until the point where the
>>> emulated emulated DDD would call HHH(DDD) again.
>> Whereupon the simulated HHH would abort, if it weren't unnecessarily
>> aborted.
> If the first HHH to meet its abort criteria does not act on this
> criteria then none of them do.
And if the first one does, all of them do.

>>>>> When HHH is an x86 emulation based termination analyzer then each
>>>>> DDD *correctly_emulated_by* any HHH that it calls never returns.
>>>> It is not a correct emulation if it has a different termination
>>>> status.
-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.