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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: People are still trying to get away with disagreeing with the
 semantics of the x86 language
Date: Thu, 4 Jul 2024 16:26:06 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <4bab17f6a6b64fce08359d2c1682df9f804c70e1@i2pn2.org>
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Am Thu, 04 Jul 2024 11:03:09 -0500 schrieb olcott:

> On 7/4/2024 10:06 AM, joes wrote:
>> Am Thu, 04 Jul 2024 08:41:22 -0500 schrieb olcott:
>>> On 7/4/2024 8:26 AM, joes wrote:
>>>> Am Thu, 04 Jul 2024 07:46:15 -0500 schrieb olcott:
>>>>> On 7/4/2024 5:15 AM, joes wrote:
>>>>>> Am Wed, 03 Jul 2024 09:45:57 -0500 schrieb olcott:
>>>>>>> On 7/3/2024 9:39 AM, joes wrote:
>>>>>>>> Am Wed, 03 Jul 2024 08:21:40 -0500 schrieb olcott:
>>>>>>>>> On 7/3/2024 3:26 AM, Fred. Zwarts wrote:
>>>>>>>>>> Op 02.jul.2024 om 21:48 schreef olcott:
>>>>>>>>>>> On 7/2/2024 2:22 PM, Fred. Zwarts wrote:
>>>>>>>>>>>> Op 02.jul.2024 om 20:43 schreef olcott:
>>>>>>>>>>>>> On 7/2/2024 1:59 AM, Mikko wrote:
>>>>>>>>>>>>>> On 2024-07-01 12:44:57 +0000, olcott said:
>>>>>>>>>>>>>>> On 7/1/2024 1:05 AM, Mikko wrote:
>>>>>>>>>>>>>>>> On 2024-06-30 17:18:09 +0000, olcott said:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> Richard just said that he affirms that when DDD
>>>>>>>>>>>>>>>>> correctly simulated by HHH calls HHH(DDD) that this call
>>>>>>>>>>>>>>>>> returns even though the semantics of the x86 language
>>>>>>>>>>>>>>>>> disagrees.
>>>>>>>> Which semantics?
>>>>>> I repeat.
>>>> What x86 semantics say that HHH can’t return?
>> Hello?

>>>>>>>>> DDD correctly emulated by HHH calls an emulated HHH(DDD) that
>>>>>>>>> emulates DDD that calls an emulated HHH(DDD)
>>>>>>>>> in a cycle that cannot end unless aborted.
>>>>>>>> But HHH aborts, so the cycle does end.
>>>>>>> As long as it is impossible for DDD correctly emulated by HHH to
>>>>>>> reach its own ret instruction then DDD never halts even when its
>>>>>>> stops running because its emulation was aborted.
>>>>>> HHH halts by definition. Why can’t DDD?
>>>>> By definition DDD calls its simulator.
>>>> Yes, and nothing else. So when HHH returns, so does DDD.
>>> *Machine address 00002174 of DDD is never reached*
>> Why not? Clearly HHH halts. Does it not return or what?
> The semantics of the x86 language proves that DDD correctly emulated by
> HHH cannot possibly reach its own machine address 00002183.
What semantics am I disagreeing with? Doesn’t HHH halt?

-- 
Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:
Objectively I am a genius.